From the calculation, the force constant is 192 N. Also, friction would decrease the extension.
<h3>What is the force constant?</h3>
We know that the force constant can be obtained by the use of the relation;
F = Ke
F = applied force
K = force constant
e = extension
We know from Hooks law that the force applied is directly proportional to the extension.
We can write;
F = mgcosθ
F = 43 Kg * 9.8 m/s^2 * sin31°
F = 217 N
K = 217 N/1.13 m
K = 192 N/m
If there is friction between the incline and the crate, it will stretch less because some work will be lost due to friction causing only some fraction of the elastic potential energy to be converted to kinetic energy.
Learn more about Hooke's law:brainly.com/question/14140269
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Answer:
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Explanation:
kinda just re-worded the stuff I saw on google
Answer:
The SI unit for length is meters(m), for mass is kilograms(kg)
Explanation:
hope it helps
Answer:
correct answer is 1.20 times too high
Explanation:
Let's analyze the relationship between linear and angular variables
v = w r
where w is the angular velocity of the car, which we will assume constant, r is the radius of the tire.
the normal tire has a radius ro
v₀ = w r₀
The tire with the new radius is r = 1.20 r₀\o
v = w r
v = 1.20 w r₀
v = 1.20 v₀
so the average speed is 1.20 times higher than the real speed
so the correct answer is 1.20 times too high
Answer:
The answer is chemical energy, so that would be D
Explanation: