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laila [671]
4 years ago
5

A hollow metal sphere is electrically neutral (no excess charge). A small amount of negative charge is suddenly placed at one po

int P on this metal sphere. If we check on this excess negative charge a few seconds later we will find one of the following possibilities: a. All of the excess charge remains right around P. b. The excess charge has distributed itself evenly over the outside surface of the sphere. c. The excess charge is evenly distributed over the inside and outside surface. d. Most of the charge is still at point P, but some will have spread over the sphere. e. There will be no excess charge left.
Physics
1 answer:
anygoal [31]4 years ago
7 0

Answer and explanation:

The right answer is b) "The excess charge has distributed itself evenly over the outside surface of the sphere".

The hollow metal sphere is a conductor. This means that charges can move freely over its surface. On the other side, a metal body act as an equipotential body. Once some charge is set and there is no voltage differential imprinted over the body, to keep being an equipotential body the charges must distribute evenly on the external surface. Must not exist charge in the volume, or would exist an electrical field and therefore a voltage differential. Also, the charge distribution in the internal surface must be null. If you apply gauss theorem with a gaussian sphere with a radius between the internal and external surface, knowing that field E is null, the enclosed charge must be null.

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How does the intensity of a sound wave change if the distance from the
Alex17521 [72]

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

I=\dfrac{P}{A}

P is power

A is area

I=\dfrac{P}{4\pi r^2}

or

I\propto \dfrac{1}{r^2}, r is distance from the source

If the distance from the  source is increased by a factor of 4, r' = 4r

So,

I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}

So, the new intensity decreases by a factor of 16.

8 0
4 years ago
A 200 N resultant force acts on 350 kg object. Calculate how long it takes this force to change the objects velocity from 3 m/s
Zanzabum
5m/s because all you have to do is add 3 and 8
4 0
3 years ago
Elyse is explaining to a friend that she will be conducting a scientific investigation. Her question is "How many leatherback se
trapecia [35]

<span>The scientific investigation has  five basic steps and one feedback step: (1) to make an observation (2) to ask a question (3) hypothesize (4) predict and (5) make a new hypothesis based on the results.  What is unusual about the description of Elyse’s scientific investigation is she did not follow the basic steps. She should have done observation first before asking a question and forming a hypothesis. </span>

8 0
4 years ago
You drop an ice cube into an insulated bottle full of water and wait for the ice cube to completely melt. The ice cube initially
AVprozaik [17]

Answer:

T_{f}  = 17º C

Explanation:

This is a calorimetry problem, where heat is yielded by liquid water, this heat is used first to melt all ice, let's look for the necessary heat (Q1)  

Let's reduce the magnitudes to the SI system  

      Ice m = 80.0 g (1 kg / 1000 g) = 0.080 kg  

            L = 3.33 105 J / kg  

Water  M = 860 g = 0.860 kg  

           c_{e} = 4186 J / kg ºC

    Q₁ = m L  

     Q₁ = 0.080 3.33 10⁵

     Q₁ = 2,664 10⁴ J

Now let's see what this liquid water temperature is when this heat is released  

      Q = M c_{e} ΔT = M c_{e} (T₀₁ -T_{f1})  

      Q₁ = Q  

     T_{f1} = T₀₁ - Q / M ce  

     T_{f1} = 26.0 - 2,664 10⁴ / (0.860 4186)  

     T_{f1} = 26.0 - 7.40  

     T_{f1} = 18.6 ° C  

The initial temperature of water that has just melted is T₀₂ = 0ª  

The initial temperature of the liquid water is T₀₁= 18.6  

     m c_{e} T_{f} + M c_{e} T_{1} = M c_{e} T₀₁ - m c_{e} T₀₂o2  

         T_{f} = (M To1 - m To2) / (m + M)  

         T_{f} = (0.860 18.6 - 0.080 0) / (0.080 + 0.860)  

T_{f} = 17º C

 

gg

4 0
3 years ago
John runs 120 meters in 10 seconds and then runs back to where he started in another 10 seconds. Which statement is true? Rememb
atroni [7]

Answer:

B

Explanation:

<em>A. His speed is 0 m/s </em>

<em>B. His velocity is 12 m/s </em>

<em>C. His velocity is 0 m/s </em>

<em>D. His acceleration is 12 m/s</em>

Total distance traveled by John = 120 + 120 = 240 meters

Total time taken by John to cover the distance = 10 + 10 = 20 s

<em>Average speed of John = total distance traveled/total time taken</em>

      = 240/20 = 12 m/s

Hence, the average speed/velocity of John throughout the journey is 12 m/s.

The correct option is B.

4 0
3 years ago
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