Answer:
The figure is attached down
Step-by-step explanation:
To graph a line you must have its equation
The form of the linear equation is y = m x + b, where
- m is its slope
- b is the y-intercept (y at x = 0)
∵ The slope of the line is 
∴ y =
x + b
- To find b substitute x and y in the equation by the coordinates
of a point on the line
∵ The line passing through point (-5 , -4)
∴ x = -5 and y = -4
∵ -4 =
(-5) + b
∴ -4 =
+ b
- Subtract
from both sides
∴
= b
∴ y =
x - 
To draw the line substitute x by any two values and find their ys
∵ x = -2
∴ y =
(-2) -
∴ y = -6
∴ The line passing through point (-2 , -6)
∵ x = 1
∴ y =
(1) -
∴ y = -8
∴ The line passing through point (1 , -8)
∵ x = 4
∴ y =
(4) -
∴ y = -10
∴ The line passing through point (4 , -10)
Now we can make a table to draw the line
→ x : -5 : -2 : 1 : 4
→ y : -4 : -6 : -8 : -10
Plot the points on the graph paper and draw the line
<em>Look to the attached graph</em>
Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table
![~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=~~~~~~%5Ctextit%7Bvertical%20parabola%20vertex%20form%7D%20%5C%5C%5C%5C%20y%3Da%28x-%20h%29%5E2%2B%20k%5Cqquad%20%5Cbegin%7Bcases%7D%20%5Cstackrel%7Bvertex%7D%7B%28h%2Ck%29%7D%5C%5C%5C%5C%20%5Cstackrel%7B%22a%22~is~negative%7D%7Bop%20ens~%5Ccap%7D%5Cqquad%20%5Cstackrel%7B%22a%22~is~positive%7D%7Bop%20ens~%5Ccup%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
![\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}](https://tex.z-dn.net/?f=%5Cstackrel%7Bvertex%7D%7B%5Cstackrel%7Bh%7D%7B-1%7D~~%2C~~%5Cstackrel%7Bk%7D%7B-4%7D%7D%5Cqquad%20%5Cimplies%20y%3Da%5Bx-%28-1%29%5D%5E2-4%5Cimplies%20y%3Da%28x%2B1%29%5E2-4%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Bwe%20also%20know%20that%7D%20%5Cbegin%7Bcases%7D%20x%3D2%5C%5C%20y%3D14%20%5Cend%7Bcases%7D%5Cimplies%2014%3Da%282%2B1%29%5E2-4%5Cimplies%2018%3D9a%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B18%7D%7B9%7D%3Da%5Cimplies%202%3Da~%5Chspace%7B10em%7D%5Cboxed%7By%3D2%28x%2B1%29%5E2-4%7D)
Answer:
1) x<2.5 2) x<2.5 (both are smaller numbers than 2.5)
Step-by-step explanation:
I'm sure there is a easier way to figure this question out but how I did is by simply imputing numbers smaller or bigger into where the x is. For example, I imputed 3 into -4x+5>-5. So, -4(3)+5>5, = -7>5, this is false, so x must be smaller than 2.5 in order for this to be true.
This cannot be simplified anymore
Given, a = 1
common difference = 3
Eighth term = a+(n-1)d = 1+(8-1)3
= 1 + 21 = 22
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>