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Eddi Din [679]
3 years ago
12

Suppose that Mudlark decides to sell 140 tickets for this flight. Assuming that all 140 tickets are sold and that the outcome fo

r each ticketholder is independent, how many ticketholders should the airline expect to show up
Mathematics
1 answer:
Julli [10]3 years ago
3 0

This question is incomplete, the complete question is;

Lets consider a hypothetical airline, Mudlark Airlines. On one of its flight, previous records show that about 15% of people who had tickets for the flight did not take the flight. There are 120 seats on the plane.

Suppose that Mudlark decides to sell 140 tickets for this flight. Assuming that all 140 tickets are sold and that the outcome for each ticketholder is independent, how many ticketholders should the airline expect to show up

Answer: the airline should expect 119 ticketholders to show up

Step-by-step explanation:

Given that;

the plane contains 120 seats

Their records shows that 15% (0.15) percent of people who previously buy their flight tickets don't show up.

they sold 140 tickets,

Number of ticketholder expected to show up  = ?

Probability of showing up for flight will be;

⇒ 1 - 0.15 = 0.85

Now Expected number of ticketholders to shup will be;

⇒ 140 × 0.85

= 119

Therefore the airline should expect 119 ticketholders to show up

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3 years ago
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lana66690 [7]

Answer:

(7) n = ⁴/₃

(8) x = -5

(9) d = ³/₂

(10) v = -20

Step-by-step explanation:

(7) n-\frac{8}{9} = \frac{4}{9}

n-\frac{8}{9} = \frac{4}{9} \\\\Collect \ similar \ terms \ together\\\\n = \frac{4}{9} + \frac{8}{9} \\\\n = \frac{4+8}{9} \\\\n = \frac{12}{9} \\\\n = \frac{4}{3}

(8)

\frac{3}{2} + \ x = -\frac{7}{2}\\\\collect \ similar \ terms \ together\\\\x = -\frac{7}{2}  -\frac{3}{2} \\\\x = \frac{-7-3}{2} \\\\x = \frac{-10}{2} \\\\x = -5

(9)

\frac{6}{5} = \frac{d}{(\frac{5}{4} )} \\\\cross \ and \ multiply\\\\5d = 6(\frac{5}{4} )\\\\5d = \frac{30}{4} \\\\d = \frac{30}{4\times 5} \\\\d = \frac{30}{20} \\\\d = \frac{3}{2} \\\\d = 1\frac{1}{2}

(10)

-\frac{1}{8} v = \frac{5}{2} \\\\\frac{-v}{8} = \frac{5}{2} \\\\cross \ and \ multiply\\\\-2v = 40\\\\-v = \frac{40}{2} \\\\-v = 20\\\\v = -20

6 0
3 years ago
Grandma gives 180 marbles to her ten grandchildren. No two children get the same amount of marbles. Betsy gets the most. What is
SOVA2 [1]

Answer:

23 marbles

Step-by-step explanation:

Number of children = 10

Number of marbles = 180

Since Betsy gets the most and no 2 children gets the same number of marbles

The least number of marbles Betsy could get will be x ; with the other 9 children receiving 1 less each

That is :

Betsy = x

9th child = x - 1

8th child = x - 2,... 1st child = x - 9

Hence,

(x + x - 1 + x - 2 + x - 3 + x - 4 + x - 5 + x - 6 + x - 7 + x - 8 + x - 9) = 180

10x - 45 = 180

10x = 180 + 45

x = 225 / 10

x = 22.5

x = 23

Hence, the least Betsy could get is 23 marbles

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3 years ago
Help with this question!
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