All categories

3 years ago

Which statement is true?

Mathematics

2 answers:

IRISSAK [1]3 years ago

8 0

C is the correct answer

Marysya12 [62]3 years ago

5 0

A) False. Some rectangles do not have all four sides that are the same length.

B) False. If the four angles are not all 90 degrees, then it is a non-rectangular parallelogram.

C) True. A square is always a rectangle since a square has four right angles. The same isn't always true in reverse (as choice A mentions). A square is also always a rhombus.

D) False. It is possible to draw a four-sided figure that does not have four right angles.

Answer is choice C

You might be interested in

Lf g(x) is an odd function, which function must be an even function?

den301095 [7]

Answer: This is the real one

Step-by-step explanation:

7 0

3 years ago

What is the sum of any rational number and its opposite

xxTIMURxx [149]

The answer is 0, hope I helped you!

6 0

3 years ago

HELP FAST 100 POINTS - please show how you got it thank you

Alexandra [31]

side angle side (SAS) is the postulate because we can clearly see that two of the sides of the triangles are congruent (9 & 14), as well as the Q and T angle.

the perimeter is 43

6y+5=8y

y= 5/2

9+14+6(5/2)+5= 43

7 0

3 years ago

The slopes of the perpendicular lines are ____.

Veseljchak [2.6K]

Answer:

a) negative reciprocals

Step-by-step explanation:

8 0

3 years ago

Place the indicated product in the proper location on the grid. (a+b-c)(a+b+c)

aliina [53]

Answer:

The required location on the gird is shown below.

Step-by-step explanation:

Consider the provided expression.

We need to place the indicated product in the proper location on the grid.

First open the parenthesis as shown:

$(a+b-c)(a+b+c)=a(a+b+c)+b(a+b+c)-c(a+b+c)$

$(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2$

Now add the like terms as shown:

$(a+b-c)(a+b+c)=a^2+b^2-c^2+2ab$

Hence, the required location on the gird is $(a+b-c)(a+b+c)=a^2+b^2-c^2+2ab$

3 0

3 years ago