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3 years ago

14

Select the correct answer. Which is the simplified form of the expression ?

1 answer:

likoan [24]3 years ago

7 0

Answer:

a) b^5/12

Step-by-step explanation:

b^2/3 ÷ b^1/4 [if bases are the same then subtract the exponents]

2/3 - 1/4 = 5/12

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Find the slope of the line that crosses through the points (-2, 5) and (-5, -4)

Helen [10]

Answer:

umm i believe it is positive 5

Step-by-step explanation:

i hope i helped

5 0

3 years ago

Read 2 more answers

Need help with this question ! Due soon*

Doss [256]

Answer:

x = 10, AB = 57

Step-by-step explanation:

In a trapezoid, the length of the median is one-half the sum of the lengths of the bases. From this, we have:

$\frac{1}{2} (5x + 7 + 8x - 11) = 63$

$13x - 4 = 126$

$13x = 130$

$x = 10$

$5(10) + 7 = 50 + 7 = 57$

5 0

2 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

as

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

Gisele has $5.90 in quarters and nickels. If Gisele has 16 more nickels than quarters, how many quarters does she have? [I don't

krok68 [10]

Answer:

See below

Step-by-step explanation:

Quarters= 25(x)

Nickels =5(x+16)

25x+5(x+16)=590 (no decimal)

If you solve for x, you’ll get the number of quarters.

3 0

3 years ago

Identify the parts of the expression 4.2m + (8 , 2) - 6.

yan [13]

Answer:

The answe wo

Step-by-step explanation:

5 0

2 years ago