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Verizon [17]
3 years ago
5

Writing Equations of Parallel Lines

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0

Answer:

The slope of the parallel line to the given line is -\frac{1}{4}

The equation of the parallel line to the given line and passes through the given point is y + 4 =  -\frac{1}{4} (x + 2)

The y-intercept of the parallel line to the given line and passes through the given point is  -\frac{9}{2}

Step-by-step explanation:

  • The rule of the slope of the line that passes through points (x1, y1) and (x2, y2) is m = \frac{y2-y1}{x2-x1}
  • The point-slope form of the linear equation is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line
  • The slope-intercept form of the linear equation is y = m x + b, where m is the slope and b is the y-intercept
  • Parallel lines have the same slopes and different y-intercepts

In the given figure

∵ The given line passes through points (2, 6) and (-6, 8)

∴ x1 = 2 and y1 = 6

∴ x2 = -6 and y2 = 8

→ Substitute them in the rule of the slope above to find it

∵ m = \frac{8-6}{-6-2} = \frac{2}{-8} = -\frac{1}{4}

∴ The slope of the given line is -\frac{1}{4}  

∵ Parallel lines have the same slopes

∴ The slope of the parallel line to the given line is -\frac{1}{4}

∵ The parallel line passes through the point (-2, -4)

∴ x1 = -2 and y1 = -4

∵ m = -\frac{1}{4}

→ Substitute them in the point-slope form above

∵ y - (-4) = -\frac{1}{4} (x - (-2))

∴ y + 4 =  -\frac{1}{4} (x + 2)

∴ The equation of the parallel line to the given line and passes through

   the given point is y + 4 =  -\frac{1}{4} (x + 2)

∵ m = -\frac{1}{4}

→ Substitute it in the slope-intercept form above

∴ y =  -\frac{1}{4} x + b

→ To find b substitute x by -2 and y by -4 (coordinates the given point)

∵ -4 = -\frac{1}{4}(-2) + b

∴ -4 = \frac{1}{2} + b

→ Subtract  \frac{1}{2}  from both sides

∴ -\frac{9}{2} = b

∵ b is the y-intercept

∴ The y-intercept of the parallel line to the given line and passes

   through the given point is  -\frac{9}{2}

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