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3 years ago

Help!!! 10 points dhdhdhhhshmsmhsm

Mathematics

1 answer:

Citrus2011 [14]3 years ago

6 0

Second one sorry if i’m wrong

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Long-billed curlews eat many different kinds of insects, including grasshoppers, as a source of food. It has been shown that pes

dezoksy [38]

11.12 ask your teacher abt it

3 0

2 years ago

Find the coordinates of the midpoint of line AB given the coordinates: A(-1, 5) B(2,-3)*

Naily [24]

Answer:

$\bold{M_{AB}\left(\frac12\,,\ 1\right)}$

Step-by-step explanation:

The midpoint of AB coordinates are: $M_{AB}\left(x_M\,,\ y_M\right)$ where:

$x_M=\frac{x_A+x_B}2=\frac{-1+2}2=\frac12\\\\y_M=\frac{y_A+y_B}2=\frac{5+(-3)}2=\frac{2}2=1$

6 0

4 years ago

What would be the next number after 5;12:21:32..

pantera1 [17]

Your answer would be 45... do u want me to explain?

5 0

3 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

4 years ago

Convert to the product of multiplication a^2-b^2-4b-4

kirill [66]

$a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

Step-by-step explanation:

We know that factors are the numbers that are being multiplied together . As 6532*7 = 45724 .Here 6532 & 7 are the factors and 45724 is product of the factors .

Here , we need to convert to the product of multiplication

a^2-b^2-4b-4 or , $a^2-b^2-4b-4$ :

⇒ $a^2-b^2-4b-4$

We know by identity that , $p^2-q^2 = (p-q)(p+q)$

⇒ $(a-b)(a+b)-4b-4$

Taking common term out as -4 :

⇒ $(a-b)(a+b)-4(b+1)$

Therefore , $a^2-b^2-4b-4$ in form of multiplication is $(a-b)(a+b)-4(b+1)$ .

7 0

3 years ago