Question

Chuge%7B%5Cunderline%7B%5Cbf%7B%5Cgreen%7Bfactorise%3A%20-%20%20%7D%7D%7D%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%5Chuge%7B%5Cboxed%7B%5Csf%7B%5Cpurple%7B2x%20%7B%7D%5E%7B2%7D%20%2B%209x%20%2B%2010%20%7D%7D%7D%7D%7D" id="TexFormula1" title="\huge\mathfrak\red{please \: solve \: } \\ \\ {\huge{\underline{\bf{\green{factorise: - }}}}} \\ \\ {\huge{\boxed{\sf{\purple{2x {}^{2} + 9x + 10 }}}}}" alt="\huge\mathfrak\red{please \: solve \: } \\ \\ {\huge{\underline{\bf{\green{factorise: - }}}}} \\ \\ {\huge{\boxed{\sf{\purple{2x {}^{2} + 9x + 10 }}}}}" align="absmiddle" class="latex-formula">
​

Answer 1

Answer:

Why Do I only See Code Here?

Step-by-step explanation:

Strange...

What is This Things?

Answer 2

Answer:

(x + 2)(2x + 5)

Step-by-step explanation:

2x^2 + 9x + 10 =

This is a trinomial of the form ax^2 + bx + c, where a is not 1.

Step 1: Try to factor out a common factor.

In this case, there is no common factor in all terms.

We will now factor by grouping.

Step 2. Find the product ac.

ac = 2 * 10 = 20

Step 3. Find two factors of ac whose product is ac and whose sum is b.

In this case, we need two numbers whose product is 20 and whose sum is 9.

Those numbers are 4 and 5.

Step 4. Break up the middle term using the two numbers we just found.

9x becomes 4x + 5x

Now we have

= 2x^2 + 4x + 5x + 10

Step 5. Factor by grouping. Factor a common factor out of the first two terms. Factor a common factor out of the last two terms.

= 2x(x + 2) + 5(x + 2)

Finally, factor out the common factor, x + 2.

= (x + 2)(2x + 5)

Answer: (x + 2)(2x + 5)