$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$9000\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\

t=years\to &9
\end{cases}
\\\\\\
A=9000\left(1+\frac{0.06}{2}\right)^{2\cdot 9}$

7 0

3 years ago

Pls help me with this — show work pls

lianna [129]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the magnitude of AB. A(-2, 6), B(1, 10) O A 2 OB. ✔️15 O C.5 OD ✔️2

natita [175]

Answer:

C. 5

Step-by-step explanation:

Use the Distance Formula.

Substitute the values of x1 , y1 , x2 , and y2 .

|AB|² =|(1--2)²+(10-6)²|

|AB|² = |9+16|

|AB| = √ 25

|AB| =5

6 0

3 years ago