Answer:
<h3>444m</h3>
Step-by-step explanation:
Given the height of the rocket modelled by the equation;
y=-16x^2+152x+83
The rocket reaches its maximum height when the velocity of the rocket is zero.
Since velocity is the change in displacement with respect to time;
velocity v = dy/dx
dy/dx = -32x + 152
at dy/dx = 0
-32x + 152 = 0
-32x = -152
x = -152/-32
x = 4.75s
To get maximum height reached by the ball, we will substitute x = 4.75 into the modeled function as shown;
y(4.75) = -16(4.75)^2+152(4.75)+83
y(4.75) = -361+722+83
y(4.75) = 444m
Hence the maximum height reached by the ball is 444m
Jason = 142 cm = 1.42 m
Amy = 137 cm = 1.37 m
Joseph = 1397 mm = 1.397 m
From shortest to tallest
I) Amy, Joseph, Jason
You would have to find the y intercepts.
X + Y = 20
Substitute 0 for y then your answer would be 20 for x.
Substitute 0 for x then your answer would be 20 for y.
X=20
Y=20
Hope it helped! : )
