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Given:
The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).
To find:
The area of the rectangle.
Solution:
Distance formula:
Using the distance formula, we get
Similarly,
Now, the length of the rectangle is and the width of the rectangle is
. So, the area of the rectangle is:
Therefore, the area of the rectangle is 20 square units.
rearrange into the form y = mx + b
subtract 6x from both sides of the equation
7y = - 6x + 14
divide all terms by 7
y = - x + 2 → in slope- intercept form