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3 years ago

Quadrilateral QRST is an isosceles trapezoid. Q(-3,-2); S(3,2); T(5,-2). what would point R be?

Mathematics

1 answer:

MariettaO [177]3 years ago

3 0

Here it is graphed... But I'm not sure what the x value of R would be... I know its Y value is 2

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Without drawing the graphs, find the points of intersection of the lines: a 7x+4y=23 and 8x–10y=19

emmainna [20.7K]

Answer:

(3,0.5)

Step-by-step explanation:

The given system has equations:

$7x + 4y = 23 \\ 8x - 10y = 19$

Let us multiply the second equation by 4 and the first equation by 10.

$70x + 40y = 230 \\ 32x - 40y = 76$

We add both new equations to get:

$102x = 306 \\ x = \frac{306}{102} = 3$

Put x=3 into the first equation and solve for y.

$7(3) + 4y = 23 \\ 21 + 4y = 23 \\ 4y = 23 - 21 \\ 4y = 2 \\ y = \frac{1}{2}$

The point of intersection is the solution to the system of equation which is (3,0.5)

8 0

3 years ago

The line a bus arrives at the bus stop every 25 minutes and the line B bus arrives every 15 minutes. Both are at the bus stop ri

Tpy6a [65]

They will be there for 40 minutes because 25+15 is 40

6 0

3 years ago

A restaurant has 2,006 forks, 1,745 knives, and 1,898 spoons. The owner wants to have the same number of each utensil. She can b

balandron [24]

If she wanted to buy new utensils she could buy 108 spoons and 261 knifes then she would have 2,006 forks, spoons, and knifes. Or she could donate 261 forks and 153 spoons and have 1,745 of each utensils.

7 0

2 years ago

Read 2 more answers

Whats the answer for y - 6 > -7

lakkis [162]

Answer:

y>−1

Step-by-step explanation:

y-6>-7

Add 6 to both sides

y-6+6 > -7+6

Simplify

y>-1

7 0

2 years ago

Let’s assume that, over the years, a paper and pencil test of anxiety yields a mean score of 35 for all incoming college freshme

vovangra [49]

Answer:

|t| = 2.235 > 2.093

we rejected null hypothesis.

It is not coming from population

Step-by-step explanation:

Step:-1

Let’s assume that, over the years, a paper and pencil test of anxiety yields a mean score of 35 for all incoming college freshmen.

μ = 35

small sample size n =20

mean of the sample x⁻ = 30

standard deviation of (S) = 10

Null hypothesis :- The difference between x⁻ and μ is not significant

Alternative hypothesis:- The difference between x⁻ and μ is significant

that is μ ≠ 35

Level of significance :-∝ =0.05

The test statistic:-

$t = \frac{x^{-} - population mean}{\frac{S}{\sqrt{n} } }$

substitute all values in above equation

μ = 35 ,n =20

mean of the sample x⁻ = 30

standard deviation of (S) = 10

$t = \frac{30 - 35}{\frac{10}{\sqrt{20} } }$

t= -2.235

|t| = 2.235

The degrees of freedom γ =n-1 =20-1 =19

By tabulated value of 't' for 19 degrees of freedom at 5% level of significance.= 2.093 for two tailed test.(see attached diagram below)

conclusion:-

|t| = 2.235 > 2.093

we rejected null hypothesis.

It is not coming from population

8 0

3 years ago