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marusya05 [52]
3 years ago
13

Quadrilateral QRST is an isosceles trapezoid. Q(-3,-2); S(3,2); T(5,-2). what would point R be?

Mathematics
1 answer:
MariettaO [177]3 years ago
3 0
Here it is graphed... But I'm not sure what the x value of R would be... I know its Y value is 2

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Janice's mother gave her a $10 bill to buy 5 pounds each of bananas and apples at the grocery store when she got there she find
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No, Janice's mom didn't give her enough money.
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A scale drawing has a scale of 1/4 centimeters equal to 10 meters. What is the unit rate of centimeters to meters
lozanna [386]

Answer:

  • 1 cm to 40 m
  • 1/40 cm to 1 m

Step-by-step explanation:

The problem statement isn't clear as to which unit is 1 in your unit rate. If it is 1 cm, you can find the unit rate by multiplying the reationship by 4:

... 4 × (1/4 cm to 10 m) = 1 cm to 40 m

If it is 1 m, you can find the unit rate by multiplying the relationship by 1/10:

... 1/10 × (1/4 cm to 10 m) = 1/40 cm to 1 m

_____

<em>Additional comment on the problem</em>

Ordinarily, drawing scales are expressed as a fraction. Here, that would be ...

(1/4×1/100 m)/(10 m) = 1/4000 . . . or . . . 1 : 4000

3 0
3 years ago
Find the area of the shape​
exis [7]

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I CANNOT ANSWER THE QUESTION WITHOUT KNOWING THE SHAPE

3 0
3 years ago
ASAP WILL MARK BRAINLYEST <br><br>solve these four please!!
s2008m [1.1K]

I dont know if you wanted the steps but:

x^2-4x-6=0

plug it into the equation:

\frac{-(-4)\sqrt{(-4)^2-4(1)(-6)}}{2(1)}

[tex] \frac{4\sqrt{40}}{2} [/tex]

\frac{4+2\sqrt{10}}{2}    \frac{4-2\sqrt{10}}{2}

x=2+\sqrt{10}

x=2-\sqrt{10}

x^2-4/3x+1/3 x=1 , x= 1/3

2x^2-3x+1=0 x=1 , x=1/2

6x^2+12x=-5

add the 5 to both sides

6x²+12x+5=0 plug the problem into the equation

x=\frac{-12\sqrt{12^{2}-4(6)(5)}}{2(6)}

x=[\frac{-12\sqrt{144-120}}{12}

x=\frac{-12\sqrt{24}}{12}

x=\frac{-12+2\sqrt{6}}{12} x=\frac{-12-2\sqrt{6}}{12}

\frac{-6+2\sqrt{6}}{6} \frac{-6-2\sqrt{6}}{6}


7 0
3 years ago
PLEASE HELP! HURRY!<br>QUESTIONS ARE IN THE PICTURE
Andreyy89

Happy New Year from MrBillDoesMath!

Answer:

    #1:       If two sides.....

  #2:       congruent by the SSS congruence postulate


Thank you,

MrB

3 0
3 years ago
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