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3 years ago

20. (01.03 MC) What is the simplified expression ? (1 point)

Mathematics

1 answer:

ahrayia [7]3 years ago

4 0

Answer:

$\displaystyle 3^2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Exponential Rule [Multiplying]: $\displaystyle b^m \cdot b^n = b^{m + n}$
Exponential Rule [Dividing]: $\displaystyle \frac{b^m}{b^n} = b^{m - n}$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{3^3 \cdot 3^3}{3^4}$

Step 2: Simplify

[ER] Multiply: $\displaystyle \frac{3^{3+3}}{3^4}$
Add Exponents: $\displaystyle \frac{3^6}{3^4}$
[ER] Divide: $\displaystyle 3^{6 - 4}$
Subtract Exponents: $\displaystyle 3^2$

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If | x + 4 | = 1, what value(s) could x have?

dybincka [34]

Answer:

-5 and -3 could both work in this situation

Step-by-step explanation

-5 + 4 = -1

| -1 | = 1

-3 + 4 = 1

| 1 | = 1

7 0

3 years ago

Vivian surveyed bicyclists in her community to see the average number of miles they biked per day. Her results are shown below.

Alex

Answer:

MAD of her data set is 4.

Step-by-step explanation:

Vivian surveyed bicyclists in her community to see the average number of miles they biked per day.

The data set is given below :

7, 10, 13, 4, 12, 21, 10, 3

$mean=\frac{\text{Sum of data set}}{\text{number of values}}$

$=\frac{(7+10+13+4+12+21+10+3)}{8}$

$=\frac{80}{8}$

= 10

$MAD=\frac{\sum |A_1-f_1|}{n}$

Data point Distance from mean

1 7 7 - 10 = | -3 | = 3

2. 10 10 - 10 = | 0 | = 0

3. 13 13 - 10 = | 3 | = 3

4. 4 4 - 10 = | -6 | = 6

5. 12 12 - 10 = | 2 | = 2

6. 21 21 - 10 = | 11 | = 11

7. 10 10 - 10 = | 0 | = 0

8. 3 3 - 10 = | -7 | = 7

Adding the distance = 3 + 0 + 3 + 6 + 2 + 11 + 0 + 7 = 32

MAD = $\frac{32}{8}$ = 4

MAD of her data set is 4.

Mean Absolute Deviation of this data tells about the variation of 4 miles biked each day by the bicyclists.

6 0

3 years ago

FREE BRAINLIEST ! Find the slope of the line that passes through: (-3, -4) and (7, 6)

d1i1m1o1n [39]

Answer:

10/10 =1 / 1 =1

m = ^^

Step-by-step explanation:

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3 years ago

I need help ASAP please! Giving brainliest!!

aksik [14]

The correct answer is C

3 0

3 years ago

Read 2 more answers

Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal. (Enter your answers as a comma-separated list.)

Gala2k [10]

Answer:

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

Step-by-step explanation:

Orthogonal vectors

Suppose we have two vectors:

$v_{1} = (a,b,c)$

$v_{2} = (d,e,f)$

Their dot product is:

$(a,b,c).(d,e,f) = ad + be + cf$

They are ortogonal is their dot product is 0.

Solving quadratic equations:

To solve this problem, we are going to need tosolve a quadratic equation.

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4a$

Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal.

$(4,x,-6)(2,x,x) = 8 + x^{2} - 6x$

These vectors are going to be orthogonal if:

$x^{2} -6x + 8 = 0$

This is a quadratic equation, in which $a = 1, b = -6, c = 8$ . So

$\bigtriangleup = 6^{2} - 4*1*8 = 4$

$x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4$

$x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2$

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

3 0

4 years ago