Thvuvugufugy i need help pls i beg

krok68 [10]

      3x + 4
2x + 5|6x² + 23x + 20
   6x² + 15x
      8x + 20
      8x + 20
      0
The answer is B.

(2n³ + 4n² - 7) + (-n³ - 8n - 2)
(2n³ - n³) + 4n² - 8n - 7 - 2
n³ + 4n² - 8n - 9
The answer is B.

2x² - 10x - 12
2(x²) - 2(5x) - 2(6)
2(x² - 5x - 6)
2(x² - 3x - 2x - 6)
2(x(x) - x(3) - 2(x) - 2(3))
2(x(x - 3) - 2(x - 3))
2(x - 2)(x - 3)
The answer is A.

4ab - 8a² + 12ac = 4ab - 8a² + 12ac = b - 2a + 3c
      4a    4a    4a    4a
The answer is B.

5 0

3 years ago

Assume that the one-way commute time of an UoU student from his house to school is a normally distributed random variable which

Marizza181 [45]

Answer:

$n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16$

So the answer for this case would be n=16 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=10$ represent the sample standard deviation

n represent the sample size

ME=5 represent the margin of error

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (2)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (3)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (3) we got:

$n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16$

So the answer for this case would be n=16 rounded up to the nearest integer

3 0

4 years ago

Train A travels 50 miles/hour.Train A has been traveling for 25 minutes when train B set out in the same direction traveling 60

White raven [17]

The answer is 20.83......minutes

7 0

4 years ago

As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim

AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0

3 years ago

Y = 2x + 3 2 How does the equation of a line need to be changed to shift the line upward? 1 123 1 -3 -2 -1 -1 -2 A A. The absolu

Jobisdone [24]

Answer:

C

Step-by-step explanation:

8 0

3 years ago

Thvuvugufugy i need help pls i beg​

Thvuvugufugy i need help pls i beg