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Harlamova29_29 [7]
3 years ago
15

Need help fast please

Mathematics
1 answer:
madam [21]3 years ago
5 0
A circle with a radius of 5 units has a circumference of 31.416 units. Hope that helps!
You might be interested in
What is the volume of this?
Oksanka [162]

Answer:

82 in^3

Step-by-step explanation:

3 x 2 x 7      + 2 x 2 x 10    =  82 in^3

7 0
2 years ago
explain how you could use the greatest common factor of 8 and 20 in the distributive property to write 8 + 20 as a product​
GenaCL600 [577]

Answer: 4(5+2) or 4(2+5)

Step-by-step explanation:

8 = 2*2*2

20 = 2*2*5

4(5+2) = 20+8

6 0
3 years ago
Enter an equation in point-slope form for the line.<br> Slope is 9 and (−3, −1) is on the line.
Korolek [52]

Answer:

y+1=9(x+3)

Step-by-step explanation:

Since the equation for point slope form is y-y₁=m(x-x₁)

enter the given points (-3,-1)

y-(-1)=9(x-(-3))

y+1=9(x+3)           <-- point slope form

8 0
3 years ago
About 19​% of the population of a large country is hopelessly romantic. If two people are randomly​ selected, what is the probab
Aleksandr-060686 [28]

Answer:

3.61% probability that both are hopelessly romantic​.

34.39% probability at least one is hopelessly romantic

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are hopelessly romantic, or they are not. The probability of a person being hopelessly romantic is independent from other people. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

19​% of the population of a large country is hopelessly romantic.

This means that p = 0.19

Two people are randomly​ selected

This means that n = 2

What is the probability both are hopelessly romantic​?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

3.61% probability that both are hopelessly romantic​.

What is the probability at least one is hopelessly romantic​?

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.19)^{1}.(0.81)^{1} = 0.3078

P(X = 2) = C_{2,2}.(0.19)^{2}.(0.81)^{0} = 0.0361

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.3078 + 0.0361 = 0.3439

34.39% probability at least one is hopelessly romantic

7 0
3 years ago
A student used the equation below to create a table.
ddd [48]

Answer:

second option -2, -11

Step-by-step explanation:

when you put -2 where x is then

y is -11

4 0
2 years ago
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