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7nadin3 [17]
3 years ago
13

4d + 7e = 68 -4d - 6e = -72 QUICK

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Step-by-step explanation:

by adding :

e=_4

d=24.....

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Suppose the tree diagram below represents all the students in a high school and that one of these students were chosen at random
andrey2020 [161]
The question is: If the student is known to be the girl (300 girls) what is the probability of being right handed.

We know that there are 300 girls, and that out of those 300, there are 250 girls right handed. 

Divide 250 with 300

250/300 = 0.83333, or 83.33%

0.83333, or 83.33% is your answer

hope this helps
4 0
3 years ago
25 pound x 41.000 pounds
Crank
1,025 lbs I think that s the answer
7 0
3 years ago
You have a large container of mustard oil.You have used 480 quarts of oil. 76% of the oil remains. How many quarts remain?
DiKsa [7]
The best approach to take here is to find out what 1% and 10% are, then multiply them accordingly. 
To find 10%, just divide the amount of quarts by 10.
480/10= 48
Therefore, 10% is 48 quarts.
To find 1%, you then divide the 10% by 10. 
48/10= 4/8
Therefore, 1% is 4.8 quarts.
As you're looking for 76, you can either multiply the 1% by 76, or you can break it down into two parts, which may be easier, which is the method that I will use.
I would split it into 70% and 6%
As you've got 10%, in order to find 70%, you just need to multiply this by 7.
48*7= 336.
you then need to find the odd 6%.
As you've find 1%, you need to then multiply this by 6.
4.8*6= 28.8
You then need to add these together to get your total.
336+28.8= 364.8
As you're looking for the remainder, you then need to take this away from 480.
480-364.8= 115.2
Therefore, you have 115.2 quarts of mustard oil remaining.
Hope this helps :)
5 0
3 years ago
Read 2 more answers
Sally is $3.95 in dimes and quarters that shows the total 23 coins how many times does she have and how many quarters does she h
UkoKoshka [18]
Make a system of equations:

0.10x + 0.25y = 3.95
x + y = 23

x + y = 23

Subtract 'y' to both sides:

x = -y + 23

Plug in -y + 23 for 'x' in the first equation:

0.10(-y + 23) + 0.25y = 3.95

Distribute 0.10:

-0.10y + 2.3 + 0.25y = 3.95

Subtract 2.3 to both sides:

-0.10y + 0.25y = 1.65

Combine like terms:

0.15y = 1.65

Divide 0.15 to both sides:

y = 11

Plug this into any of the two equations to find 'x':

x + y = 23

x + 11 = 23

Subtract 11 to both sides:

x = 12

So Sally has 11 dimes and 12 quarters.
6 0
4 years ago
Please help with this problem. I keep getting -25
katrin [286]
\bf -\sqrt[5]{-(400^2)}\implies -\sqrt[5]{-[(20\cdot 20)^2]}\implies -\sqrt[5]{-[(20^2)^2]}
\\\\\\
-\sqrt[5]{-(20^{2\cdot 2})}\implies -\sqrt[5]{-(20)^4}\implies -\sqrt[5]{-(2^2\cdot 5)^4}
\\\\\\
-\sqrt[5]{-2^{2\cdot 4}\cdot 5^4}\implies -\sqrt[5]{-2^8\cdot 5^4}\implies -\sqrt[5]{-2^{5+3}\cdot 5^4}
\\\\\\
-\sqrt[5]{-2^5\cdot 2^3\cdot 5^4}\implies 2\sqrt[5]{2^3\cdot 5^4}\implies 2\sqrt[5]{5000}
4 0
4 years ago
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