1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
3 years ago
15

Find the product. (6xyz4)(5xy3) PLEASE HELP!!! ASAP!!

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0

Answer:

Step-by-step explanation:

Multiply each term:

30x^2y^4z^4

Plz mark me brainliest!!

Elza [17]3 years ago
6 0

Answer:

30x^2y^4z^4

Step-by-step explanation:

If we multiply 6x by 5x, we get 30x^2.

If we multiply y by y^{3}, we get y^{4}.

z stays the same, since it's not being multiplied by anything.

Hope this helped!

You might be interested in
What is the domain of the function indicated by the points on the coordinate plane?
Sophie [7]
The answer is C if not sorry
7 0
3 years ago
A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i
Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

2=\frac{1+x_{2} }{2}\\  4=1+x_{2}\\  4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0

So (12,0) it is the other endpoint.

Take a look at the graph below:

8 0
3 years ago
Help please pretty please i do not understand
Natalija [7]
If i remember correctly i think you just cross multiply   <span />
7 0
3 years ago
Read 2 more answers
Maggie volunteered to bake a cake she decided to double the recipe if the original recipe calls for 3/4 cup brown sugar how much
zlopas [31]

Answer:

3/2

Step-by-step explanation:

3/4 * 2 = 6/4 = 3/2

7 0
3 years ago
5 x 10^5 is how many times as large as 1 x 10^5?
Oxana [17]

Answer:

  5 times as large

Step-by-step explanation:

You can think of "10^5" as "green marbles" if you like. Then your question is ...

  5 green marbles is how many times as large as 1 green marble.

Hopefully, the answer is all too clear: it is 5 times as large.

_____

In math terms, when you want to know how many times as large y is as x, the answer is found by dividing y by x:

  y/x . . . . . tells you how many times as large as x is y.

Here, that looks like ...

  \dfrac{5\times 10^5}{1\times 10^5}\\\\=\dfrac{5}{1} \qquad\text{the factors of $10^5$ cancel}\\\\=5

4 0
3 years ago
Read 2 more answers
Other questions:
  • A robotic machine fills containers with an acid solution at the rate of 50 + 5 t milliliters (mL) per second, where t is in seco
    11·1 answer
  • Lines Line D E and Line A B are parallel. Lines D E and A B are parallel. Angles B and D are alternate interior angles. Which an
    5·2 answers
  • What is the answer?
    7·1 answer
  • I have no clue how to get the answer for this
    11·1 answer
  • Distributive property 22multiplyby5
    10·2 answers
  • Factor Completely: 9x^2-25
    6·1 answer
  • If you need help with Math:)
    7·2 answers
  • Slope = -2 passes through (-3,5)
    13·2 answers
  • Joe's grandma lives 36 blocks up the street from Joe. On Saturday, Joe
    15·1 answer
  • Use a proportion to find the length of side x for the pair of similar figures
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!