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madreJ [45]
3 years ago
5

PLEASE SOLVE!! IN A HURRY WILL name the BRAINLIEST!!!

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

62

Step-by-step explanation:

96 divided by 2 = 48

48 - 14 = 34

48 + 14 = 62

34 + 62 = 96 (total cars washed)

You're welcome

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Find tan 0.<br> (Marking brainliest if correct) <br><br> 8/17<br> 15/17<br> 15/8<br> 8/15
Rina8888 [55]

Answer:

15/8

Step-by-step explanation:

Assuming you mean tan theta

Tan(theta) = opposite/adjacent

We know the adjacent side is 8 so the bottom of the fraction must also be 8

C: 15/8 is the only option that fits this criteria

4 0
3 years ago
Hi- I need help please to get my HS diploma...did not graduate :(
andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

#SPJ1

8 0
2 years ago
PLZ answer ASAP!!!!! Due at midnight!!
Lapatulllka [165]
Answer: D

Good luck !
3 0
3 years ago
Read 2 more answers
How many 4 digit numbers consisting of only the digits 2,4,6 and 8 are divisible by 4
Blababa [14]

Answer:

  • digits used once: 12
  • repeated digits: 128

Step-by-step explanation:

In order for a number to be divisible by 4, its last two digits must be divisible by 4. This will be the case if either of these conditions holds:

  • the ones digit is an even multiple of 2, and the tens digit is even
  • the ones digit is an odd multiple of 2, and the tens digit is odd.

We must count the ways these conditions can be met with the given digits.

__

Since we only have even numbers to work with, the ones digit must be an even multiple of 2: 4 or 8. (The tens digit cannot be odd.) The digits 4 and 8 comprise half of the available digits, so half of all possible numbers made from these digits will be divisible by 4.

<h3>digits used once</h3>

If the numbers must use each digit exactly once, there will be 4! = 24 of them. 24/2 = 12 of these 4-digit numbers will be divisible by 4.

<h3>repeated digits</h3>

Each of the four digits can have any of four values, so there will be 4^4 = 256 possible 4-digit numbers. Of these, 256/2 = 128 will be divisible by 4.

7 0
2 years ago
Read 2 more answers
Can anyone solve this question please
levacccp [35]

Answer:

Step-by-step explanation:

by definition : The inverse of a relation consisting of points of the form (x,y) is the set of points (y,x)

if (1,7) is a point belong to f(x), then the inverse has to be (7,1) not (8,1)

3 0
3 years ago
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