X^2 + 6x - 27
(x - 3)(x + 9)
The answer is: (x - 3)(x + 9).
The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.
Now at head wind →
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
The value (9/10)*81 is greater than (5/6)*81
<h3>How to determine the greater value?</h3>
The values are given as:
(5/6)*81 and (9/10)*81
Remove the common factor in both values
So, we have:
5/6 and 9/10
Convert to decimals
0.83 and 0.9
0.9 is greater than 0.83
Hence, (9/10)*81 is greater than (5/6)*81
Read more about expressions at:
brainly.com/question/723406
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Answer:
120 Minutes
Step-by-step explanation:
24 minutes / 2 miles = 12 minutes / 1 mile
12 minutes / 1 miles = x minutes / 10 miles
Cross multiply
12*10/1 = x
120 / 1 = x
x = 120
Hope that helps!