Answer:
2944
Step-by-step explanation:
(-22-10)-92
(-32)-92
2944
Hope it is helpful for you please follow me
<span>This is a right triangle problem. c^2 = a^2 + b^2
Let b = 7 mi (Rosa's distance from home)
Let a = the east leg (Juan's distance from home
(a+1) = c (hypotenuse, distance between them)
(a+1)^2 = a^2 + 7^2
FOIL (a+1)(a+1)
a^2 + 2a + 1 = a^2 + 49
Combine like terms
a^2 - a^2 + 2a = 49 - 1
2a = 48
a =
<span>a = 24 mi, Juan's distance from home
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Answer:
1) y=8/3=2 2/3 2) x=4 3) x+10
Step-by-step explanation:
1) 10+5-7=3y
Calculate the sum or difference.
8=3y
Swap the sides of the equation.
3y=8
Divide both sides by 3.
y=8/3=2 2/3
2) -10x+5x+5=-15
Collect like terms.
-5x+5=-15
Move the constant to the right-hand side and change the sign.
-5x=-15-5
Calculate the difference.
-5x=-20
Divide both sides by -5.
x=4
3) 3x+2x-4x+10
Collect like terms.
(3+2-4)x+10
Calculate the sum or difference.
1x+10
When the term has a coefficient of 1, it doesn't have to be written.
x+10
Hope this helps :)
3.4 is the right answer i’m sure
First you have to isolate one of the equations for y=mx+b.
Then substitute the equation is made into the first equation
