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3 years ago

How do I do rate of change???

Mathematics

1 answer:

Bad White [126]3 years ago

7 0

Answer:

Step-by-step explanation:

For our problem since we only in 10 am:

I'm going to let x=4 represent the time 10:04 am

which means I'm going to let x=17 represent 10:17am.

So when x=4, y=23 miles and when x=17,y=179 miles.

You have two points.

You can use the formula $m=\frac{y_2-y_1}{x_2-x_1}$ .

Or just line the points up vertically and subtract them vertically, then put 2nd difference over first difference. Like this:

( 17 , 179)

-( 4 , 23)

-----------------------

13 156

So the slope is 156/13=12 miles/hour.

You might be interested in

identify the expression as a numerical expression or a variable expression.For variable expression, name the variable 1×12

Aliun [14]

Answer:

o7 fy hk hpxi oyli ifuod pir8

5 0

3 years ago

Find the area of the following polygons:

Art [367]

Area of ABCE:
12 x 4
= 48cm squared

Area of CDE:
To get the height of the triangle, you subtract 4 from 10.

10 - 4 = 6cm
Base = 12 cm

12 x 6 = 72cm

72 divided by 2
= 36cm squared.

48 + 36 = 84cm squared.

(if it’s asking individual areas, then it’s 48cm and 36cm)

8 0

3 years ago

Read 2 more answers

Megan was painting on a rectangular canvas, and needed a frame for it. The length of the frame is 15 inches and the width is 10

siniylev [52]

Answer:

50 inches

Step-by-step explanation:

Hi there!

$P=2l+2w$ where l is the length of the rectangle and w is the width of the rectangle

Plug in the length (15 inches) and width (10 inches)

$P=2(15)+2(10)\\P=30+20\\P=50$

Therefore, the perimeter of the frame is 50 inches.

I hope this helps!

8 0

3 years ago

There are 3 meters from A to B, 22 meters from B to C, 5 meters from C to D, and 7 meters from D to E. What is the distance from

notka56 [123]

17m

Because horizontal distance is 8m, vertical distance is 15m
So distance between A and Enid square root of 8^2+15^2

8 0

3 years ago

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago