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3 years ago

Factorise 5x + 10= ᴘʟᴀʏɪɴɢ: Who Asked (Feat: Nobody did ) ───────────⚪────── ◄◄⠀▐▐⠀►:/:⠀───○

Mathematics

2 answers:

olasank [31]3 years ago

8 0

Answer:

5(x+2)

Step-by-step explanation:

5x + 10=

Factor out 5

5(x+2)

Marysya12 [62]3 years ago

7 0

Answer:

$5(x + 2)$

Step-by-step explanation:

Get 5 out

$5x + 10 \\ 5(x + 2)$

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How do you solve this equation . Q=3a+5ac

mr_godi [17]

A "solution" would be a set of three numbers ... for Q, a, and c ... that
would make the equation a true statement.

If you only have one equation, then there are an infinite number of triplets
that could do it. For example, with the single equation in this question,
(Q, a, c) could be (13, 1, 2) and they could also be (16, 2, 1).
There are infinite possibilities with one equation.

In order to have a unique solution ... three definite numbers for Q, a, and c ...
you would need three equations.

8 0

3 years ago

The value of a $3000 computer decreases about 30% each year. write a function for the computers value V(t)

den301095 [7]

Answer:

Function for given situation is : $V(t)=3000(0.70)^t$

Value of computer after 4 years = $720.3.

Step-by-step explanation:

Given that the value of a $3000 computer decreases about 30% each year. Now we need to write a function for the computers value V(t). then we need to find about how much will the computer be worth in 4 years.

It clearly says that value decreases so that means function represents decay.

For decay we use formula:

$A=P(1-r)^t$

where P=initial value = $3000,

r= rate of decrease =30% = 0.30

t= number of years

A=V(t) = future value

so the required function is $V(t)=3000(1-0.30)^t$

or $V(t)=3000(0.70)^t$

Now plug t=4 years to get the value of computer after 4 years.

$V(4)=3000(0.70)^4$

$V(4)=720.3$

Hence final answer is $720.3.

7 0

3 years ago

Read 2 more answers

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago

PLEASE RESPOND!!!

solniwko [45]

Did you ever get the answer

5 0

3 years ago

The machinist's goal was to increase his production by at least 10% each day. Assume he achieved his goal. If he was able to mac

quester [9]

25+10%= 27.5 Hope this helps.

8 0

3 years ago

Read 2 more answers