Answer:
When Amina is 18. Saad would be;
k. 14
Step-by-step explanation:
Let "x" represent Anita's current age and let "y" represent Saad's current age, we have;
Anita's age = 2 × Saad's age
Therefore;
x = 2 × y...(1)
In 4 years, we will get;
x + 4 = 1.5 × (y + 4)...(2)
Substituting the value of x in equation (1) into equation (2), we get;
2·y + 4 = 1.5·y + 1.5 × 4 = 1.5·y + 6
2·y + 4 = 1.5·y + 6
2·y - 1.5·y = 6 - 4 = 2
0.5·y = 2
y = 2/0.5 = 4
Saad's current age = y = 4 years
From equation (1), we have;
x = 2 × y = 2 × 4 = 8
Amina's current age = x = 8 years
When Amina is 18, we have;
18 = 10 + 8 = 10 + x
Therefore, Amina would be 18 in 10 years time from now, from which we have;
Saad would be 10 years + y = 10 years + 4 years = 14 years in 10 years from now
Therefore, when Amina would be 18 years in 10 years from now Saad would be 14 years.
The answer is D plane Qpr
Answer: The inequality solves to x ≥ 42
The graph is shown below
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Explanation:
We have some unknown number x, and we're dividing by 6 to form the fraction x/6. That result is 7 or larger which means we write x/6 ≥ 7
To solve for x, we undo the division. We'll multiply both sides by 6. That's how we get to x ≥ 42
The graph will involve a number line. Plot a closed filled in circle at 42 on the number line. Shade to the right. This visually represents any number that is 42 or larger. The endpoint 42 itself is included in the solution set.
Side note: We would use an open circle if we didn't have the "or equal to" portion for the inequality sign.
Answer:
Females = 17 and males = 23
Step-by-step explanation:
Given that,
Total no of students in the class = 40
Let no. of females = x
No. of males = 6+x
ATQ,
Total students = males + females
40 = x+6+x
40-6 = 2x
34 = 2x
x = 17
Hence, there are 17 females and (6+17= 23) males.
