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UNO [17]
2 years ago
13

In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-s

haped and has a mean of 61 and a standard deviation of 8. Using the Standard Deviation Rule (as presented in the book), what is the approximate percentage of daily phone calls numbering between 53 and 69?
Mathematics
1 answer:
Radda [10]2 years ago
3 0

Answer:

68%

Step-by-step explanation:

The Standard Deviation Rule = Empirical rule formula states that:

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

From the question,

Step 1

We have to find the number of Standard deviation from the mean. This is represented as x in the formula

μ = Mean = 61

σ = Standard Deviation = 8

For x = 53

μ - xσ

53 = 61 - 8x

8x = 61 - 53

8x = 8

x = 8/8

x = 1

For x = 69

μ + xσ

69 = 61 + 8x

8x = 69 - 61

8x = 8

x = 8/8

x = 1

This falls within 1 standard deviation of the mean where: 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

Therefore, according to the Standard Deviation Rule, the approximate percentage of daily phone calls numbering between 53 and 69 is 68%

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Step-by-step explanation:

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Month
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Answer:Secondary sources are works that analyze, assess or interpret an historical event, era, or phenomenon, generally utilizing primary sources to do so. Secondary sources often offer a review or a critique. Secondary sources can include books, journal articles, speeches, reviews, research reports, and more.

Step-by-step explanation:

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2 years ago
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Dafna1 [17]
The answer is -10,368 ;)
7 0
3 years ago
HELP! I'll mark you the brainest and give you all my points !! (Show all work)
Paha777 [63]

1. F(3)= -2(3)-5

-6-5

F(3)=-11

2. F(3)= -2(3)^2-4

-6^2-4

36-4

F(3)=32

3. F(x)=−2x−5

For: x=−2, f(x) is:f(−2)=(−2×−2)−5=4−5=−1

For: x=−1, f(x) is:f(−1)=(−2×−1)−5=2−5=−3

For: x=1, f(x) is:f(1)=(−2×1)−5=−2−5=−7

For: x=2, f(x) is:f(2)=(−2×2)−5=−4−5=−9

The Range is:

{−1,−3,−7,−9}

4. -80, -110

4 0
3 years ago
Read 2 more answers
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