Answer: the one with the 12,18 and 22 step by step equation
hope this helped
Step-by-step explanation:
|2.5| because 2 and 1/2 are also 2.5 written in decimal, and the absolute value is always positive
88.21 fram is the anserer
Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
So consectuve even numbers
we know that one even number plus 2= another even number so we want to find 3 consecutive even numbers that add up to 96 or
x is the first number
x+2 is the second number
x+4 is the third number
x+x+2+x+4=96
3x+6=96
subtract 6 from both sides
3x=90
divide both sides by 3
x=30
the first number is 30
x+2=32=second number
x+4=34=third number
the numbers are 30,32,34
