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3 years ago

If g=8 what is the value if the expression g/2+3

Mathematics

1 answer:

Mekhanik [1.2K]3 years ago

5 0

Answer:

7 would be the value

Step-by-step explanation:

g = 8

8/2 + 3

8/2 = 4

4 + 3

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Help middle school question!!!

Sav [38]

Answer:

The shaded region has an area of 1400 square units

Step-by-step explanation:

Area of Compound Shapes

We are given a shape and it's required to calculate its area. The shape can be divided into three rectangles as shown in the figure attached below.

The lengths of these rectangles are x, y, and z.

The value of x can be calculated as:

x = 60 - 15 - 10 = 35

Similarly:

y = 60 - 15 = 45

z = y = 45

The first rectangle has dimensions of x by 10, thus its area is:

A1 = 35*10 = 350

The second rectangle has dimensions of 60 by 10:

A2 = 60*10 = 600

The third rectangle has dimensions y by 10:

A3 = 55*10 = 450

The shaded area is:

A = 350 + 600 + 450 = 1400

The shaded region has an area of 1400 square units

8 0

3 years ago

Read 2 more answers

a rectangular laboratory has a length equal to one and a half times its width and a perimeter of 40m. find its length and width

tresset_1 [31]

L=1.5w
P=l+w
40=2.5 w
W=16
L=1.5(16) =24

Length is 24
Width is 16

8 0

2 years ago

Read 2 more answers

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of analytical geometry is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$