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masya89 [10]
3 years ago
6

55/(4+1)+3-three cubed​

Mathematics
2 answers:
Charra [1.4K]3 years ago
6 0

Answer:38

Step-by-step explanation:

antiseptic1488 [7]3 years ago
3 0

Answer: 14

Step-by-step explanation:

First you have to do 4+1=5, then you do 55/5 and get 11, once you do that you do 11+3=14.

  I hope that this helps!!!

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Answer:

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Step-by-step explanation:

<em>In general we can write a polynomial in standard form as </em>

ax^n+bx^n^-^1+cx^n^-^2+...+px+q

<em>Given</em> 4m-2m^4-6m^2-4m+9

<em>Combine the like terms: 4m and -4m</em>

<em>4m-4m=0</em>

<em>We have 4m-4m=0</em>

<em>So, write the remaining terms</em>

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<em>Hence the answer is the standard form is</em>

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<em>But in the given options, you can choose option 2 and option 3 are in standard form.</em>

<em>Because they are in decreasing order of powers.</em>

<em>In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.</em>

<em>-2m^4-6m^2+4m+9</em>

<em>-2m^4-6m^2-4m+9</em>

<em>I hope this helps you.</em>

<em>And please comment if I need to do corrections.</em>

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