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2 years ago

Find the value of x (URGENT/GIVING BRAINLIEST)

Mathematics

1 answer:

Virty [35]2 years ago

6 0

Answer:

x=25

Step-by-step explanation:

The angles 126 and (5x+1) are equal. The equation that is used is 5x+1=126.

To solve the equation, subtract 1 from both sides

5x+1-1=5x 126-1=125.

Simplify the equation. 5x=125

Divide both sides by 5. 5x/5=x 125/5=25

You would get x=25 eventually.

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Write the function in standard form <br><br> f(x) = -5 (x-7)^2 +11

Lapatulllka [165]

3x+1=1 because it is a hard problem to solve just ask your teacher

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Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropria

TiliK225 [7]

GIVEN

The following values are given:

$\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}$

SOLUTION

The z-score for the x values 9 and 14 can be calculated using the formula:

$z=\frac{x-\mu}{\sigma}$

For x = 9:

$\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}$

For x = 14:

$\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}$

The probability can be calculated as follows:

$P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671$

The probability is 0.4671.

8 0

1 year ago

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

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2 years ago

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A compter costs 1,000 and decreases to 725 how much did it decreas??

notka56 [123]

Answer:

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Step-by-step explanation:

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2 years ago

Justin is training for a hamburger eating competition. He is eventually able to eat 15 hamburgers in 10 minutes. What is justin’

user100 [1]

Answer:

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Step-by-step explanation:

In 10 minutes, Justin can eat 15 burgers.

In 1 minute, Justin can eat 15/10 burgers.

15/10 = 1.5

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