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3 years ago

3 5/6+4 3/6=?? Can someone help me

Mathematics

2 answers:

galben [10]3 years ago

8 0

8 and 1/3rd is your answer

liubo4ka [24]3 years ago

7 0

35/6+43/6

35/6+43/6

35+43/6

78/6

13 is your answer.

Hoped I helped!

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Please help me! These are due at 3 and I’m freaking out Lol

iVinArrow [24]

Volume of sphere: $\frac{4}{3}\pi r^3$ , put $r=5 in$

Volume of cylinder:$ \pi r^2 h$, put $r=8 in, \: h=11 in$

6 0

3 years ago

-3 17/20 as a decimal

alekssr [168]

Answer:

-3.85

-3 is a whole number, it comes before the decimal point.

17/20 is a fraction so it goes on the other side.

7 0

3 years ago

Find a polynomial of degree 3 with real coefficients and zeros of -3,-1, and 4, for which f(-2)=-24

Zanzabum

We want to find a polynomial

f(x) = a x³ + b x² + c x + d

such that the roots of f are x = -3, x = -1, and x = 4, and f(x) takes on a value of -24 when x = -2.

The factor theorem for polynomials tells us that we can factorize f(x) as

a x³ + b x² + c x + d = a (x + 3) (x + 1) (x - 4)

Expand the right side:

(x + 3) (x + 1) (x - 4) = x³ - 13x - 12

So we have

a x³ + b x² + c x + d = a x³ - 13a x - 12a

In order for both sides to be equal, the coefficients of both polynomials on terms of the same degree must be equal. This means

a = a (of course)

b = 0 (there is no x² term on the right)

c = -13a

d = -12a

We also have that f (-2) = -24, which means

f (-2) = a (-2 + 3) (-2 + 1) (-2 - 4)

-24 = 6a

a = -4

which in turn tells us that c = 52 and d = 48.

So we found

f(x) = -4x³ + 52x + 48

4 0

2 years ago

Median of 70 61 87 85 72 65 86 80 90 60 63 81 75 77 67

liberstina [14]

I am pretty sure that the median is 80, correct me if I'm wrong :)

7 0

3 years ago

Read 2 more answers

Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe

solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for $p$ such that $1000p(1-p)$ is maximized. Once we have that $p$ , we can easily find the answer to part b.

Finding the value that maximizes $1000p(1-p)$ is the same as finding the value that maximizes $p(1-p)$ , just on a smaller scale. So, we really want to maximize $p(1-p)$ . To do this, we will do a trick called completing the square.

$p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4$ .

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of $p$ such that the inner part of the square term is equal to $0$ .

$p-1/2=0\\p=1/2$ .

So, the answer to part a is $\boxed{1/2}$ .

We can then plug $1/2$ into the equation for p to find the answer to part b.

$1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250$ .

So, the answer to part b is $\boxed{250}$ .

And we're done!

3 0

2 years ago