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BlackZzzverrR [31]
3 years ago
11

An opaque bag contains 5 blu marbles, 4 green marbles, and 3 red marbles. If two consecutive marbles are drawn without replaceme

nt what is the probability that the first one will be red and the second one will be blue?
Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

Probability[Choosing red and blue consecutive] = 5/44

Step-by-step explanation:

Given:

Number of blue marble = 5

Number of green marble = 4

Number of red marble = 3

Find:

Probability[Choosing red and blue consecutive]

Computation:

Probability of red marble = Number of red marble / Total marble

Probability of red marble = 3 / [5 + 4 + 3]

Probability of red marble = 3 / 12

Probability of red marble = 1/4

Probability of next blue marble = Number of blue marble / [Total marble - 1]

Probability of next blue marble = 5 / [Total marble - 1]

Probability of next blue marble = 5 / [12 - 1]

Probability of next blue marble = 5 / 11

Probability[Choosing red and blue consecutive] = Probability of red marble x Probability of next blue marble

Probability[Choosing red and blue consecutive] = [1/4][5/11]

Probability[Choosing red and blue consecutive] = 5/44

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Step-by-step explanation:

If it has a slope of 3/4, then it will look like this:

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3 years ago
Two numbers have prime factorizations of 2 2 · 3 · 5 and 2 · 3 2 · 7.
ladessa [460]
I think for the question above, instead of 2 · 3^2 · 7 it is <span>2 · 3^2 · 5.
</span>
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<span>To create the LCM, you choose, for each base factor in either number, the greatest exponented one. Thus, LCM needs a factor 2 squared, 3 squared, and 5, giving LCM = 4(9)(5) = 180.</span><span />
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3 years ago
Read 2 more answers
No
zhuklara [117]
It’s B 20 students I am sure that’s correct
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