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Dovator [93]
3 years ago
5

A plane travels a distance of 22,000km in a time of 3.6 hours. What is its average speed rounded to the nearest whole number

Mathematics
1 answer:
fredd [130]3 years ago
4 0

Answer:6111 km/hr

Step-by-step explanation:

Given

Distance travels by plane d=22,000 km

time taken t=3.6 hours

\text{distance}=\text{speed}\times\text{time}

average speed

v_{avg}=\dfrac{22,000}{3.6}=6111.11\approx 6111\ km/hr

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\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
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Answer:

Here are some things that could help.

Step-by-step explanation:

PEMDAS/GEMDAS

Parentheses/grouping

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Multiplication

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Adding

Subtracting

Example:

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Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

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\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

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\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

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