The simplest form of 21:28 is 3:4. you just divide both numbers by the greatest common factor.
Answer: A = $1503.6
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1 + r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 1000
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
t = 7 years
Therefore,.
A = 1000(1 + 0.06/1)^1 × 7
A = 1000(1.06)^7
A = $1503.6
Answer:
120 ≤ 20c + 40s
Step-by-step explanation:
(Assuming her name is Kylie, who is giving 40 minute science sessions and 20 minute Chinese sessions.)
The unit for time will be minutes.
Write an equation for time needed for science sessions
40s = t
Write an equation for time needed for Chinese sessions
20c = t
Combine the two equations for the total time.
20c + 40s = total time
She does not want the total time to be more than two hours.
Convert two hours to minutes. There are 60 minutes in an hour.
2h * 60mins = 120 mins
Therefore t ≤ 120. Include this into the equation.
120 ≤ 20c + 40s
Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So, 
is 37°. We can see from the diagram that 
would be 
143°.
Also, the new bearing is N 25°E. So, 
would be 25°.
Now we can find 
. As the sum of the internal angle of a triangle is 180°.
Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.
So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
<u><em>U = 40/3</em></u>
<u><em>Hope this helps :-)</em></u>
