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Jet001 [13]
3 years ago
12

Construct an equation that has k = 9 as its solution. Use k on both sides of the equation.

Mathematics
1 answer:
pentagon [3]3 years ago
4 0

Answer:

10k ÷ 10 + 1 = k + 1

Step-by-step explanation:

LHS

10k ÷ 10 + 1

10(9) ÷ 10 + 1

90 ÷ 10 + 1

10

RHS

k + 1

9 + 1

10

10k ÷ 10 + 1 = 10

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It contains three 3 pure gold
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3 years ago
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Mr. Kim's age in years is 6 more than 3 times the age of his daughter. Mr. Kim is 48 years old. How old, in years is Mr. Kim's d
gregori [183]

Answer:

14

Step-by-step explanation:

48 - 6 = 42

42 divided by 3 = 14.

Mr. Kim's daughter is 14 years old.

3 0
3 years ago
Please I need an answer asap​
attashe74 [19]

Answer:

N= 4

Step-by-step explanation:

y^3 * y^n

_______  = y^6    

   y

First we multiply the 2 y's together to get

y^n+3

____         = Y^6

Y

Then we will multiply y to both sides

y^n+3 = y^7

Get rid of y

n+3 = 7

n=4

8 0
3 years ago
Jamie is baking scones.The recipe he is following says that 455g of flour will make 8 scones.How much flour will he need to make
iren2701 [21]

Answer:

1.365k

Step-by-step explanation:

455(3)= 1365

we do this because 8(3) = 24

8 0
3 years ago
An object is launched upward from 62.5 meters above ground level with an initial velocity of 12 meters per second. The gravitati
mixas84 [53]

Answer:

5 seconds

Step-by-step explanation:

This follows the pattern

h(t)=-4.9t^2+v_{0}t+h_{0}

It is parabolic and it is used to model projectile motion.  This is the model you would use.  Now for the math of it.

The v₀ is the initial velocity and the h₀ is the initial height.  The whole thing is negative because it is an upside down parabola.  Our initial velocity is 12 and the initial height is 62.5.  That means that our particular model is

h(t)=-4.9t^2+12t+62.5

h(t) is the height of the projectile after a certain length of time, t, has gone by.  We want to know how long, t, it takes the projectile to hit the ground.  When something is laying on the ground, its height is 0.  Therefore, in order to find how long it takes for the height to be 0, we replace h(t) with 0 and then factor to find the values of t:

0=-4.9t^2+12t+62.5

If you plug this into the quadratic formula you will get that the values of t are

t = -2.55 and t = 5

We all know that the 2 things in math that will never EVER be negative are time and distance/measures, so we can disregard the negative value of time and say that the length of time it takes for the object to hit the ground from its initial height of 62.5 m is 5 seconds.

5 0
4 years ago
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