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evablogger [386]
3 years ago
13

A scientist has two solutions, which she has labeled Solution A and Solution Each contains salt. She knows that Solution A is 40

% salt and Solution B is 55% salt. She wants to obtain 90 ounces of a mixture that is 45% salt. How many ounces of each solution should she use?
Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Let the number of ounces of

A = x

B = y

A scientist has two solutions, which she has labeled Solution A and Solution Each contains salt. She knows that Solution A is 40% salt and Solution B is 55% salt. She wants to obtain 90 ounces of a mixture that is 45% salt. How many ounces of each solution should she use?

Our system of equations is given as

x + y = 90.... Equation 1

x = 90 - y

40% × x + 55% × y = 45% × 90 ounces

0.4x + 0.55y = 40.5....Equation 2

We substitute 90 - y for x in Equation 2

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Answer:  The average of the first two test scores is 97.

Step-by-step explanation:  Given that Kristie has taken five tests in science class. The average of all five of Kristie's test scores is 94 and the average of her last three test scores is 92.

We are to find the average score of her first two tests.

Let a1, a2, a3, a4 and a5 be teh scores of Kristle in first , second, third, fourth and fifth tests respectively.

Then, according to the given information, we have

\dfrac{a1+a2+a3+a4+a5}{5}=94\\\\\Rightarrow a1+a2+a3+a4+a5=94\times5\\\\\Rightarrow a1+a2+a3+a4+a5=470~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

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\dfrac{a3+a4+a5}{3}=92\\\\\Rightarrow a3+a4+a5=92\times3\\\\\Rightarrow a3+a4+a5=276~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Subtracting equation (ii) from equation (i), we get

(a1+a2+a3+a4+a5)-(a3+a4+a5)=470-276\\\\\Rightarrow a1+a2=194\\\\\Rightarrow \dfrac{a1+a2}{2}=\dfrac{194}{2}\\\\\Rightarrow \dfrac{a1+a2}{2}=97.

Thus, the average of the first two test scores is 97.

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