Answer: 8.3 minutes
Step-by-step explanation:
The time t may be obtained using the speed distance equation s=d/t. Rearranged to solve for time it would be: t=s/v, where s is the distance between the Sun and Earth and v is the speed of light.
Answer:
Solution is given by (-2,-1)
Step-by-step explanation:
2x-3y = -1
11x-9y = -13
Multiplying equation 1 by -3 and adding it to equation 2 ,we get
-6x+9y = 3
11x -9y = -13
___________
5x = -10
gives x = -2
plugging this value in equation (1) ,we get
2(-2) -3y = -1
-4 -3y =-1
-3y =-1+4
-3y =3
y = -1
solution is (-2,-1)
Answer:
scale factor(k)=23
A(x,y)=A'(kx,ky)
Let's do by using this formula
C(9,0)=C'(kx,ky)(here x=9 and y=0)
C(9,0)=(23*9,23*0)
C(9,0)=(207,0)
A(0,3)=A'(kx,ky)(here x=0 and y=3)
A(0,3)=A'(23*0,23*3)
A(0,3)=A'(0,69)
Step-by-step explanation:
sorry i dont know how to do B no
Answer:
The water rises at a rate of 16/(9π) ft/min or approximately 0.566 ft/min.
Step-by-step explanation:
Volume of a cone is:
V = ⅓ π r² h
Using similar triangles, we can relate the radius and height of the water to the radius and height of the tank.
r / h = R / H
r / h = 3 / 12
r = ¼ h
Substitute:
V = ⅓ π (¼ h)² h
V = ¹/₄₈ π h³
Take derivative with respect to time:
dV/dt = ¹/₁₆ π h² dh/dt
Plug in values:
4 = ¹/₁₆ π (6)² dh/dt
dh/dt = 16 / (9π)
dh/dt ≈ 0.566
The water rises at a rate of 16/(9π) ft/min or approximately 0.566 ft/min.
