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2 years ago

12

Angle 3 is 65 degrees. solve for x if angle 5 is equal to 5x.

1 answer:

kkurt [141]2 years ago

3 0

Answer:

X=23

Step-by-step explanation:

If angle 3 measures 65 degrees the so does angle 2, 7 and 6. By the definition of parallel lines. Then by the definition of supplementary lines angle 5+ angle 7=180 degrees, so 5x+65=180 => 5x=115 => $\frac{5x}{5}$ = $\frac{115}{5}$ => x=23.

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(K² – 30k - 18 - 4K²) ÷ (3+k).

Alexxandr [17]

Answer:

$k^2-30k-18-4k^2=(k+3)(-3k-21)+45$

Step-by-step explanation:

Given:

$(k^2-30k-18-4k^2):(3+k)$

Consider the expression $k^2-30k-18-4k^2$ . First, add the like term $k^2$ and $-4k^2:$

$k^2-4k^2=-3k^2$

Now, this expression is

$-3k^2-30k-18$

Divide $-3k^2-30k-18$ by $k+3.$ Multiply $k+3$ by $-3k$ and subtract the result from the $-3k^2-30k-18$ to eliminate the highest term $-3k^2:$

$-3k^2-30k-18-(-3k)(k+3)=-3k^2-30k-18+3k^2+9k=-21k-18$

Multiply $k+3$ by -21 and subtract the result from $-21k-18:$

$-21k-18-(-21)(k+3)=-21k-18+21k+63=45$

Hence,

$k^2-30k-18-4k^2=(k+3)(-3k-21)+45$

6 0

2 years ago

Find the general solution of<br><br> dz/dt=5ze^(sint)cost+2e^(sint)cost

gizmo_the_mogwai [7]

Answer:

The general solution of given differential equation is $\frac{1}{5}ln|5z+2|=e^{\sin t}+C$ .

Step-by-step explanation:

The given differential equation is

$\frac{dz}{dt}=5ze^{\sin t}\cos t+2e^{\sin t}\cos t$

Taking out common factors.

$\frac{dz}{dt}=(5z+2)e^{\sin t}\cos t$

Using variable separable method, we get

$\frac{dz}{5z+2}=e^{\sin t}\cos t dt$

Integrate both sides.

$\int\frac{dz}{5z+2}=\int e^{\sin t}\cos t dt$

$I_1=I_2$ .... (1)

First solve LHS,

$I_1=\int\frac{dz}{5z+2}$

Substitute $5z+2=u$

$5\frac{dz}{du}=1$

$dz=\frac{1}{5}du$

$I_1=\frac{1}{5}\int\frac{du}{u}$

$I_1=\frac{1}{5}ln|u|+C_1$

$I_1=\frac{1}{5}ln|5z+2|+C_1$

Now, solve RHS,

$I_2=\int e^{\sin t}\cos t dt$

Substitute $\sin t=v$ ,

$\cos t\frac{dt}{dv}=1$

$\cos tdt=dv$

$I_2=\int e^{v}dv$

$I_2=e^{v}+C_2$

$I_2=e^{\sin t}+C_2$

Subtitle the values of I₁ and I₂ in equation (1).

$\frac{1}{5}ln|5z+2|+C_1=e^{\sin t}+C_2$

$\frac{1}{5}ln|5z+2|=e^{\sin t}+C_2-C_1$

$\frac{1}{5}ln|5z+2|=e^{\sin t}+C$

Therefore the general solution of given differential equation is $\frac{1}{5}ln|5z+2|=e^{\sin t}+C$ .

4 0

2 years ago

I don't know how to do this

Artemon [7]

Answer:

i dont ethier ;i

Step-by-step explanation:

3 0

2 years ago

PLEASE NO SPAM!!!! I NEED HELP!!!! PLEASE!

ratelena [41]

Using finite difference, the answer is cubic. Apologies if I’m wrong

5 0

2 years ago

Read 2 more answers

What is the length and the width of a rectangle with perimeter of 48 inches if its length is 7 inches longer than its width.

sattari [20]

Answer:

Length and the width of the rectangle is 15.5 inches and 8.5 inches respectively.

Step-by-step explanation:

Given:

Length = 7 inches + Width

=> P = 48 inches

=> L = (7 + W) inches............. (1)

Perimeter 'P' is the sum of all sides of the rectangle 2 (L + W)

∴ 48 inches = 2 (L + W) .................(2)

Substitute for L in equation (2)

∴ 48 inches = 2 [(7 + W) + W]

48 = 2[7 + 2W]

48 = 14 +4W

48 - 14 = 4W

34 = 4W

W = 8.5 inches

Recall that: Length, L = (7 + W)

∴ L = (7 + 8.5)

L = 15.5 inches

4 0

2 years ago

Read 2 more answers