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Mazyrski [523]
3 years ago
15

Solve for x. 7x - = 6x - O x = 1/4 Ox=1 Ox= -1 O x = -1/4 Will give brainly

Mathematics
2 answers:
madam [21]3 years ago
6 0

Answer:

-1/4

Step-by-step explanation:

0.375=3/8 0.625=5/8

7x-0.375=6x-0.625

1x=-0.25

-0.25=-1/4

Leokris [45]3 years ago
5 0

Answer:

D. - 1/4

Step-by-step explanation:

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9*3.14 = 28.26

(This solves for circumference)

300/28.26 = 10.6157

(This solves for rotations)

About 11 rotations.

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Natali5045456 [20]

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Select all that are undefined csc(pi) cot(pi/2) cot(pi) sec(45 degrees) csc(0 degrees) sec(90 degrees)
lorasvet [3.4K]

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Csc(pi)

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2 years ago
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What is the value of 2 in 255.6
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200?

Step-by-step explanation:

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3 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
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