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3 years ago

9

Kevin entered a pie eating contest. He ate 4 pies in 132 seconds. What is kevins unit rate? Awnser without units.

1 answer:

Anestetic [448]3 years ago

3 0

Answer:

Kevin eats 1 pie for every 33 seconds that pass

Step-by-step explanation:

A unit rate is a rate with 1 in the denominator. If you have a rate, such as price per some number of items, and the quantity in the denominator is not 1, you can calculate unit rate or price per unit by completing the division operation: numerator divided by denominator.

If we were wondering how many seconds Kevin takes to eat a pie then the equation would look like:

132 seconds / 4 pies = 33 seconds per pie

33 seconds / 1 pie

However, if we were looking for how many pies Kevin eats in a second, then the equation would look like:

4 pies / 132 = .0303 or 3.03% of a pie per second

.0303 pies / 1 second

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Create four equations using 9, 54 and 6 fact families

Contact [7]

9 * 6 = 54
6 * 9 = 54

These would be 2 of the 4 equations, because 6 times 9 equals 54 and 9 times 6 equals 54, but are written in a different way. Thus meaning they are 2 of the 4 equations.

54/6 = 9
54/9 = 6

These 2 would be the final to, because 54 divided by 6 is 9, and 54 divided by 9 is 6. Thus meaning they are the final 2 equations.

I hope this helps!

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3 years ago

I dont know how to do thiss can someone help

lesantik [10]

Step-by-step explanation:

REO=RBO=67

BOR=ERO=91

REB=REO-BE0=67-32=35

RYE=180-ERO-REB=180-91-35=54

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3 years ago

2x^2=9-3x <br> Find the factors

d1i1m1o1n [39]

Answer:

x = -3, $\frac{3}{2}$

Step-by-step explanation:

The given quadratic equation is: $2x^2 = 9 - 3x$

This can be written as: $2x^2 + 3x - 9 = 0$

To solve a quadratic equation of the form $ax^2 + bx + c = 0$ we use the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)}$

$\implies x = \frac{-3 \pm \sqrt{81}}{4}$

$\implies x = \frac{-3 \pm 9}{4}$

We get two values of 'x', viz.,

x = $\frac{-3 + 9}{4}$ and $\frac{- 3 - 9}{4}$

$\implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4}$

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $\frac{3}{2}$ ) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $\frac{3}{2}$ to see that this indeed is the given quadratic equation.

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bagirrra123 [75]

Answer:

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Step-by-step explanation:

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