What point is a solution for the linear inequality x−3y≥4?

Mathematics

1 answer:

alexgriva [62]3 years ago

8 0

Answer:

(4,0)

Step-by-step explanation:

when x−3y≥4 is graphed it goes through the point (4,0)

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disa [49]

Answer:

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Step-by-step explanation:

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Shelia's measured glucose level one hour after a sugary drink varies according to the normal distribution with μ = 132 mg/dL and

Lelechka [254]

Answer:

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Step-by-step explanation:

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identify an equation in point slope form for the line perpendicular to the y=-1/2x+11 that passes through (4,-8). a. y+8=1/2(x-4

Solnce55 [7]

Answer:

d. y+8=2(x-4)

Step-by-step explanation:

There are 2 important parts to this question. First, understanding which slopes are perpendicular. The negative reciprocal of a number will be perpendicular to it. So, since the original slope is -1/2 the new slope should be 2.

Then, remember what the point-slope formula is. The point-slope formula is: $y-y_{2}=m(x-x_{2})$ . So if you plug in the point and slope the new equation looks like, $y--8=2(x-4)$ . Then, simplify for the final answer of $y+8=2(x-4)$ .