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kkurt [141]
3 years ago
12

If RT and UW are parallel lines and m

Mathematics
1 answer:
Levart [38]3 years ago
3 0

Answer:

The angle would be 113 too

Step-by-step explanation:

Both are parallel with the same line going through then both so they would have the same angle.

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This circle graph shows where students in two sixth-grade classes volunteer after school. Fifty students were surveyed. What per
Akimi4 [234]
The answer is 22% because you just divide 11 by 50 and move the decimal 2 spaces to the right.
6 0
3 years ago
can somebody help me simplify this given radical to the lowest form√112a^2 and try to explain it to me in layman's terms
posledela

\bf \sqrt{112a^2}~~ \begin{cases} 112=2\cdot 2\cdot 2\cdot 2\cdot 7\\ \qquad 2^2\cdot 2^2\cdot 7\\ \qquad (2^2)^2\cdot 7 \end{cases}\sqrt{(2^2)^2\cdot 7\cdot a^2}\implies 2^2a\sqrt{7}\implies 4a\sqrt{7}

6 0
3 years ago
Examine whether x-1 is a factor of the polynomial 4x³+3x²-4x+3​
Yuki888 [10]

Answer:

x - 1 is not a factor.

Step-by-step explanation:

By the Factor theorem if  x - 1 is a factor then f1) = 0:

f(1) = 4*1^3 + 3*1^2 - 4*1 + 3

=  4 + 3 - 4 + 3

= 6 so it is not a factor.

4 0
4 years ago
This equation shows how Rita's video game score is related to the number of coins she collects. p = 20c The variable c represent
djverab [1.8K]

Answer:

1 coin

Step-by-step explanation:

Given that c is number of coins, p the points collected and 20 is the constant.

-The equation for total points is p=20c, therefore, we calculate the number of coins as:

p=20c, \ p=20\\\\20=20c\\\\c=1

#Hence, Rita only has to collect 1 coin to earn 20 points.

4 0
3 years ago
Question part points submissions used use newton's method with the specified initial approximation x1 to find x3, the third appr
serious [3.7K]

Set f(x)=2x^3-3x^2+2. Find the tangent line \ell_1(x) to f(x) at the point when x=x_1:

f'(x)=6x^2-6x\implies f'(x_1)=12 (slope of \ell_1)

\implies\ell_1(x)=12(x-x_1)+f(x_1)=12(x+1)-3=12x+9

Set x_2=-\dfrac9{12}, the root of \ell_1(x). The tangent line \ell_2(x) to f(x) at x=x_2 has slope and thus equation

f'(x_2)=\dfrac{63}8\implies\ell_2(x)=\dfrac{63}8\left(x+\dfrac9{12}\right)-\dfrac{17}{32}=7x+\dfrac{151}{32}

which has its root at x_3=-\dfrac{151}{224}\approx-0.6741.

(The actual value of this root is about -0.6777)

5 0
3 years ago
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