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3 years ago

If RT and UW are parallel lines and m

Mathematics

1 answer:

Levart [38]3 years ago

3 0

Answer:

The angle would be 113 too

Step-by-step explanation:

Both are parallel with the same line going through then both so they would have the same angle.

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This circle graph shows where students in two sixth-grade classes volunteer after school. Fifty students were surveyed. What per

Akimi4 [234]

The answer is 22% because you just divide 11 by 50 and move the decimal 2 spaces to the right.

6 0

3 years ago

can somebody help me simplify this given radical to the lowest form√112a^2 and try to explain it to me in layman's terms

posledela

$\bf \sqrt{112a^2}~~ \begin{cases} 112=2\cdot 2\cdot 2\cdot 2\cdot 7\\ \qquad 2^2\cdot 2^2\cdot 7\\ \qquad (2^2)^2\cdot 7 \end{cases}\sqrt{(2^2)^2\cdot 7\cdot a^2}\implies 2^2a\sqrt{7}\implies 4a\sqrt{7}$

6 0

3 years ago

Examine whether x-1 is a factor of the polynomial 4x³+3x²-4x+3

Yuki888 [10]

Answer:

x - 1 is not a factor.

Step-by-step explanation:

By the Factor theorem if x - 1 is a factor then f1) = 0:

f(1) = 4*1^3 + 3*1^2 - 4*1 + 3

= 4 + 3 - 4 + 3

= 6 so it is not a factor.

4 0

4 years ago

This equation shows how Rita's video game score is related to the number of coins she collects. p = 20c The variable c represent

djverab [1.8K]

Answer:

1 coin

Step-by-step explanation:

Given that c is number of coins, p the points collected and 20 is the constant.

-The equation for total points is p=20c, therefore, we calculate the number of coins as:

$p=20c, \ p=20\\\\20=20c\\\\c=1$

#Hence, Rita only has to collect 1 coin to earn 20 points.

4 0

3 years ago

Question part points submissions used use newton's method with the specified initial approximation x1 to find x3, the third appr

serious [3.7K]

Set $f(x)=2x^3-3x^2+2$ . Find the tangent line $\ell_1(x)$ to $f(x)$ at the point when $x=x_1$ :

$f'(x)=6x^2-6x\implies f'(x_1)=12$ (slope of $\ell_1$ )

$\implies\ell_1(x)=12(x-x_1)+f(x_1)=12(x+1)-3=12x+9$

Set $x_2=-\dfrac9{12}$ , the root of $\ell_1(x)$ . The tangent line $\ell_2(x)$ to $f(x)$ at $x=x_2$ has slope and thus equation

$f'(x_2)=\dfrac{63}8\implies\ell_2(x)=\dfrac{63}8\left(x+\dfrac9{12}\right)-\dfrac{17}{32}=7x+\dfrac{151}{32}$

which has its root at $x_3=-\dfrac{151}{224}\approx-0.6741$ .

(The actual value of this root is about -0.6777)

5 0

3 years ago