Ask question

Ask question

All categories

3 years ago

7

In a class of students, the following data table summarizes how many students play

2 answers:

antiseptic1488 [7]3 years ago

7 0

Answer:

19/28

Step-by-step explanation:

People who count: 4 + 2 + 13 = 19

Total amount of pplz: 19 + 9 = 28

prisoha [69]3 years ago

7 0

Answer:

15/28

Step-by-step explanation:

The total amount of students in the class is 28. This will be useful for later.

From this table, we can see that 2 people play sports alone and 13 play an instrument alone. Since it says the number of students that play a sport or an instrument, this means that the top left box is not counted. This leaves you with an answer of 15/28.

You might be interested in

LM and N O are parallel lines what therom can we prove by translating the plane along the directed line segment M N?

Nezavi [6.7K]

Answer:

no idea lol

Step-by-step explanation:

6 0

2 years ago

What is the answer 7÷5,631 eqall

otez555 [7]

7/5,631=0.0012431185

3 0

3 years ago

In New York State's Quick Draw lottery, players choose between one and ten numbers that range from 1 1 to 80 . 80. A total of 20

amid [387]

Answer:

b

Step-by-step explanation:

7 0

3 years ago

Find the equation of the line that passes through points A and B.<br> y<br> X A (4, 7)<br> B (2, 3)

g100num [7]

Answer:

y = 2x - 1.

Step-by-step explanation:

The slope = (7-3)/(4-2)

= 4/2

= 2.

y - y1 = m(x - x1)

Here m = 2 , x1 = 2 and y1 = 3. So we have:

y - 3 = 2(x - 2)

y = 2x - 4 + 3

y = 2x - 1.

We have used the point (2, 3) to find the equation but we could have used (4, 7). We would have got the same answer.

3 0

3 years ago

Read 2 more answers

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

3 years ago