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Elden [556K]
2 years ago
14

Question 3 of 10

Mathematics
1 answer:
GREYUIT [131]2 years ago
5 0

Answer: A B

Step-by-step explanation: I need one more brainliest for next rank I’d appreciate it

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you are building a rectangular wading pool you want the area of the bottom to be 90 ft squared you want the length of the pool t
katrin2010 [14]
We can form a system of equations:
x*y=90
and
x=2y+3.
Solving gives dimensions of 15 feet by 6 feet.
8 0
3 years ago
48<img src="https://tex.z-dn.net/?f=4%5Csqrt%7Bx%7D%2012192%5C%5C" id="TexFormula1" title="4\sqrt{x} 12192\\" alt="4\sqrt{x} 121
pentagon [3]

Answer:

= x 3048

Step-by-step explanation:

6 0
2 years ago
Can someone please help me I’ll give brilliant thingy
cricket20 [7]

Answer:

Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.

Step-by-step explanation:

For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.

In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.

To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.

9/6 = 3/2

12/8 = 3/2

15/10 = 3/2

Alternatively:

6/9 = 2/3

8/12 = 2/3

10/15 = 2/3

Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.

Given that both conditions are satisfied, then we can say these triangles are similar.

Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.

Cheers.

8 0
2 years ago
HELPP it’s angles of a triangle much appreciated !
bulgar [2K]

Answer:

The coastline of alaska is longer than the entire coastline of the lower forty-eight states

3 0
2 years ago
How do I find the values of these
skad [1K]
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions   \bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}

solve for JK

\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9&#10;\\\\\\&#10;108+9KG=198

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or \bf \cfrac{12}{12+10}

3 0
3 years ago
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