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Elden [556K]
3 years ago
14

Question 3 of 10

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer: A B

Step-by-step explanation: I need one more brainliest for next rank I’d appreciate it

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Which calculation could not be used to find the percentage change
bogdanovich [222]

Answer:

Option (B).

Step-by-step explanation:

Percentage change between two numbers a and b can be calculated by the formula,

% change = \frac{|b-a|}{a}\times 100

Where, (b - a) = Change in values

a = Initial value

If a = 16 and b = 20

Percentage change between 16 and 20 will be,

= (\frac{20-16}{16})\times 100

= \frac{4}{16}\times 100

= 25%

If a = 20 and b = 16,

Percentage change = \frac{|16-20|}{20}\times 100

                                 = 20%

Therefore, %change between 16 and 24 may be 16% or 20%.

Option (A),

\frac{20-16}{16}\times 100 = 25%

Option (B),

\frac{20}{16}-1\times 100 = 1.25 - 1 × 100

                   = 1.25 - 100

                   = -98.75%

Option (C),

100\times \frac{1}{4} = 25%

Option (D),

\frac{(20-16)}{20}\times 100 = 20%

Therefore, we can not use the calculation used in Option (B).

6 0
3 years ago
Can u please help me find the value of each variable?
jarptica [38.1K]

The arc measure, which corresponds to the central angle measure, is always twice the subtended angle.

So 60 is twice a,

Answer: a=30

84 is twice b

Answer: b=42

60 + 100 is twice c,

Answer: c=80

d is what's left of the circle, total 360 degrees,

d = 360 - 84 - 60 - 100 = 116

Answer: d=116

3 0
3 years ago
What is the value of \dfrac{d}{dx}\left(\dfrac{2x+3}{3x^2-4}\right) dx d ​ ( 3x 2 −4 2x+3 ​ )start fraction, d, divided by, d, x
stellarik [79]

Answer:

4.

Step-by-step explanation:

We are asked to find the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1.

First of all, we will find the derivative of the given expression using "Quotient Rule of Derivatives" as shown below:

(\frac{f(x)}{g(x)})'=\frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{(g(x))^2}

\frac{d}{dx}(\frac{2x+3}{3x^2-4})

\frac{\frac{d}{dx}(2x+3)*(3x^2-4)-(2x+3)*\frac{d}{dx}(3x^2-4)}{(3x^2-4)^2}

\frac{2*(3x^2-4)-(2x+3)*(6x)}{(3x^2-4)^2}

\frac{6x^2-8-12x^2-18x}{(3x^2-4)^2}

\frac{-6x^2-18x-8}{(3x^2-4)^2}

Therefore, our required derivative is \frac{-6x^2-18x-8}{(3x^2-4)^2}.

Now, we will substitute x=-1 in our derivative to find the required value as:

\frac{-6(-1)^2-18(-1)-8}{(3(-1)^2-4)^2}

\frac{-6(1)+18-8}{(3(1)-4)^2}

\frac{-6+18-8}{(3-4)^2}

\frac{4}{(-1)^2}

\frac{4}{1}

4

Therefore, the value of expression \frac{d}{dx}(\frac{2x+3}{3x^2-4}) at x=-1 is 4.

6 0
3 years ago
Solve each system by substitution<br><br>-5x+3y=22<br>8x-2y=-24​
Ivan

x= 193/22y= 1410/11

8 0
3 years ago
Read 2 more answers
Good Morning! I need help ASAP!<br> What's a 4/9 of 72KG?
UkoKoshka [18]

Answer:

32

Step-by-step explanation:

First divide 72 by 9 which is 8. Then multiply that by 4 which is 32

7 0
3 years ago
Read 2 more answers
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