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Airida [17]
3 years ago
15

the 5th graders at beeville elementary are attending the holiday performance in the auditorium there are 476 students a row can

hold nine students how many students will sit in the last row?
Mathematics
2 answers:
Brrunno [24]3 years ago
8 0
9 student because if each row holds nine then the last row must hold nine
Paladinen [302]3 years ago
8 0
8 because 476 divided by 9 gives you 52 with a remainder of 8
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How is (5^-3) written as repeated multiplication?
stich3 [128]

Answer:

To write repeated multiplication of the same number in exponential notation, first write the number being multiplied as the base. Then count how many times that number is used in the multiplication, and write that number as the exponent.

Step-by-step explanation:

5 0
2 years ago
Find the value of x. Round to the nearest tenth of the right triangle. hypotenuse is 25, bottom leg is 13, and angle is x
Verizon [17]
OK so we know that the other side is 12 because the right triangle has to have two sides that add up to the hypotenuse, and I believe it gives you the answer in the question because you are trying to find x which it says x is the angle, and since its a right triangle, it would be 90°
7 0
3 years ago
PLEASE HELP ME!!! ILL GIVE BRAINLIEST!!!
Zolol [24]

Answer: A

Step-by-step explanation:

it all refelects over the x=6

7 0
3 years ago
Read 2 more answers
the piggybank had 25.65 in dimes and quarters if there were 20 more quarters than dimes, how many dimes were in the piggybank
Nadusha1986 [10]
X = number of dimes
y = number of quarters
---
10x + 25y = 2565
y = x + 20
---
put the system of linear equations into standard form
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10x + 25y = 2565
x - y = -20
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = 59
y = 79
4 0
3 years ago
Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward
Andru [333]
Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k

-24=3a
divide both sides by 3
-8=a

-2=a+k
-2=-8+k
add 8 to both sides
6=k

the equation is
y=-8(x-4)^2+6
3 0
3 years ago
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