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3 years ago

Determine if the triangles are congruent. If yes, by which theorem?

Mathematics

1 answer:

satela [25.4K]3 years ago

3 0

Answer:

Yes and it is showing HL

Step-by-step explanation:

Its showing HL because hl is when the hypotenuse and the leg of a right triangle are the same that's exactly what is being shown in the two triangles

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How is the graph of y=2(3)^x+1 translated from the graph of y = 2(3)^x

umka2103 [35]

y=2(3)x+1

−

y=2(3)x

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the answer would be 0=1

but if it is asking u if it is false or true it is

0=1 is false, therefore the system of equations has no solutions

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4 years ago

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mihalych1998 [28]

Answer:

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Step-by-step explanation:

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3 years ago

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Sphinxa [80]

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3 years ago

Read 2 more answers

Type the correct answer in the box. Round off your answer to the nearest integer.

Ugo [173]

Answer:

59°

Step-by-step explanation:

In triangle DAB, by Pythagoras theorem:

$DB= \sqrt {6^2 +5^2} =\sqrt{36+25}=\sqrt{61}$

Next, in triangle DCB, by Pythagoras theorem:

$DB= \sqrt {(\sqrt {61} )^2 - 4^2} =\sqrt{61-16}=\sqrt{45}$

Now, by sin rule.

$\frac{ \sin \: p}{ \sqrt{45} } = \frac{ \sin 90 \degree}{ \sqrt{61} } \\ \\ \frac{ \sin \: p}{ 6.70820393} = \frac{ 1}{ 7.81024968 } \\ \\ \sin \: p = \frac{ 6.70820393}{7.81024968} \\ \\ \sin \: p = 0.858897501 \\ \\p = 59.19301883 \degree \\ \\ p \approx 59 \degree$

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3 years ago

Find the ninth partial sum of infinite sumnation 3i-4

snow_tiger [21]

$\bf \sum\limits_{i=1}^9\ 3i-4\implies \sum\limits_{i=1}^9\ 3i-\sum\limits_{i=1}^9\ 4\implies 3\sum\limits_{i=1}^9\ i-\sum\limits_{i=1}^9\ 4
\\\\\\
3\cdot \cfrac{9(9+1)}{2}-(9\cdot 4)$

and surely you know how much that is.

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3 years ago