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3 years ago

Please help!! Express the function graphed on the axes below as a piecewise function.

Mathematics

1 answer:

Anton [14]3 years ago

5 0

I tried to send the picture vertically, but the bottom part was cut off. So I turned it horizontally. Please understand that.

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PLEASE HELP!! I'LL GIVE YOU THE BRAINLIEST!!!

disa [49]

1. C. 130 = 1.5p-50

2. C. $3.19

4.(-6,12); (2,8)

5. (2,-9)

Hope this helps. :)

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3 years ago

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What is central and inscribed angle

kow [346]

Answer:

An inscribed angle is an angle formed by two chords in a circle which have a common endpoint. This common endpoint forms the vertex of the inscribed angle. The other two endpoints define what we call an intercepted arc on the circle. The intercepted arc might be thought of as the part of the circle which is "inside" the inscribed angle.

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3 years ago

PLSS HELPP 25 POINTS AND BRAINLIEST

Genrish500 [490]

Answer:

144

Step-by-step explanation:

9*3=27

27*4=108

6^2=36

108+36=144

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3 years ago

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Calculate the slope between the points: (4, -9) and (5, 1)

12345 [234]

Answer:

The answer is A- m=10

Step-by-step explanation:

The way to find slope is known as "Rise over Run" meaning the increase of Y over the increase of X. The increase of Y is 10 because 1 - (-9) = 10. The increase of X is 1 because 5 - 4 = 1. 10 over 1, or 10 / 1, equals 10.

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4 years ago

Identify the vertex, roots, and equation of the function below.

spayn [35]

The equation of a parabola in vertex form, is:

$y=a(x-h)^2+k$

Where (h,k) are the coordinates of the vertex.

From the given graph, notice that the coordinates of the vertex are:

$(5,6)$

The roots are the values of x where the graph crosses the x-axis. In this case, the graph crosses the x-axis at the points (4,0) and (6,0). Then, the roots are:

$\begin{gathered} x_1=4 \\ x_2=6_{}_{} \end{gathered}$

Substitute the values of the vertex into the equation of the parabola in vertex form:

$y=a(x-5)^2+6$

To find the value of a, substitute (x,y)=(4,0):

$\begin{gathered} 0=a(4-5)^2+6 \\ \Rightarrow0=a(-1)^2+6 \\ \Rightarrow0=a+6 \\ \Rightarrow-6=a \\ \Rightarrow a=-6 \end{gathered}$

Therefore, the equation of the parabola is:

$y=-6(x-5)^2+6$

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1 year ago