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Masteriza [31]
3 years ago
14

I need help asap please i'm really stuck on this

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0

Answer:

A=342 ft^2 (dark section)

A = 108 ft^2 (light section)

Step-by-step explanation:

Zarrin [17]3 years ago
5 0

Answer:

A=342 ft^2 (dark section)

A = 108 ft^2 (light section)

Step-by-step explanation:

18 x 25 = 450

9 x 12 = 108

450-108= 342

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Hey so.... do any of you guys have brainly plus l can use for my homework!!!!!​
Aleks04 [339]

Answer:

ha? maybe

Step-by-step explanation:

amm im not really sure

4 0
3 years ago
Find the approximate area (in square inches) of a regular pentagon whose apothem measures 9 in.
ch4aika [34]
The answer is 21.6 hope this helps
5 0
3 years ago
And art teacher has 1 and 1/2 pounds of red clay and 3/4 lb of yellow play the teacher mixes the red clay in the yellow clay tog
aksik [14]

Answer:

There is a total of 2 1/4 lb of clay. Divide that amongst the class.

8 0
4 years ago
What is the remainder when 3x^2-7x+5 is divided by x+5
Bond [772]

answer

f(-5)=115

Step-by-step explanation:

x+5=0

x=-5

f(x)=3x^2-7x+5

f(-5)=3*(-5)^2-7(-5)+5

f(-5)=3*25+35+5

f(-5)=115

5 0
3 years ago
i already have the answers but i need to show my work. ill tell you my insta and please show me a picture of the work :))
Elodia [21]

Answer:

1:

{( - 6)}^{2}  \times  {( - 6)}^{5}

from law of indices:

{a}^{n}  \times  {a}^{m}  =  {a}^{(n + m)}

therefore:

= ( - 6) {}^{ \{2 + 5 \}}  \\  = ( - 6) {}^{7}  \\  = { \boxed{ \boxed{ - 279936}}}

2:

- 4 {a}^{5} (6 {a}^{5} ) \\  = ( - 4 \times 6)( {a}^{5}  \times  {a}^{5} ) \\  =  - 24  \{{a}^{(5 + 5)}  \} \\  = { \boxed{ \boxed{ - 24 {a}^{10} }}}

3:

( - 7 {a}^{4} b {c}^{3} )(5a {b}^{4}  {c}^{2} ) \\  = ( - 7 \times 5)( {a}^{4}  \times a)(b \times  {b}^{4})  \times ( {c}^{3}  \times  {c}^{2} ) \\  =  - 35 {a}^{5}  {b}^{5 }  {c}^{5}  \\  = { \boxed{ \boxed{ - 35 {(abc)}^{5} }}}

4:

\frac{ {8}^{15} }{ {8}^{13} }

from law of indices:

\frac{a {}^{n} }{ {a}^{m} }  =  {a}^{(n - m) }  \\

therefore:

=  {8}^{(15 - 13)} \\ { \boxed{ \boxed{ {8}^{2} = 64 }}}

follow the procedure for application to other questions.

<em>Any</em><em> </em><em>question</em><em>,</em><em> </em><em>be</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em>.</em><em> </em>Thank you …

6 0
3 years ago
Read 2 more answers
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