When you divide the number of permutations of 11 objects taken 3 at a time by 3!, you will get the number of combinations of 11
objects taken 3 at a time.
1 answer:
Answer:
Yes
Step-by-step explanation:
Permutation :
nPr = n! ÷ (n - r)!
nCr = n! ÷ (n-r)!r!
11 objects taken 3 at a time :
11P3 = 11! ÷ (11 - 3)!
11P3 = 11! / 8!
11P3 = (11 * 10 * 9 )
11P3 = 990
Dividing by 3!
3! = 3*2*1 = 6
= 990 / 6
= 165
For combination :
11C3 = 11! ÷ 8!3!
11C3 = (11 * 10 * 9) / (3 * 2 * 1)
11C3 = 990 / 6
11C3
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Answer:
A) 13
Step-by-step explanation:
l // m
9x + 10 = 127
9x = 117
x = 13
Answer:
A = 10.5%
B = 28.9%
C = 39.5%
D = 18.4%
F = 2.6%
Step-by-step explanation:
Add all the frequencies together = 38
- 4/38 × 100 = 10.5%
- 11/38 × 100 = 28.9%
- 15/38 × 100 = 39.5%
- 7/38 × 100 = 18.4%
- 1/38 × 100 = 2.6%
10.5 + 28.9 + 39.5 + 18.4 + 2.6 = 100%
Answer: 145
Step-by-step explanation: You just add the angles together so 110+35=145
Answer:
4y
Step-by-step explanation:
every part of the equation can be evenly divided by 4 and y
so this leaves you with 4y (-4
+ 3y - 1)
