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3 years ago

Answer two questions about Equations A and B: A. 2x – 1 = 5x B. -1= 32

Mathematics

1 answer:

kicyunya [14]3 years ago

7 0

A. -1/3 B. False it doesnt equal each other

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The cost of a car rental is $30 per day plus 18c per mile. You are on a daily budget of $75. Write and solve an inequality to

Tanzania [10]

Answer:

2. 5 miles

Step-by-step explanation:

Given that:

Rental cost = $30

Cost per mile driven = 18 cent

Daily budget = $75

Greatest distance you can drive each day while staying within budget :

Rental cost + (cost per mile driven * distance) ≤ daily budget

$30 + 18d ≤ $75

18d ≤ 75 - 30

18d ≤ 45

d ≤ 45 / 18

d ≤ 2.5

Greatest distance you can drive each day while staying within budget is 2.5 miles.

8 0

3 years ago

So I have another math question that involves the same problem and so is 7 + 7x the same as 7x+ 7 i think it is but i'm not sure

BartSMP [9]

Answer:

it is

Step-by-step explanation:

because it addition it doesn't matter which way you put it

6 0

2 years ago

Read 2 more answers

F(x)=x2+1<br> g(x)=2x-5<br> Find f(x)-g(x)

Alona [7]

Answer:

Step-by-step explanation:

x^2 + 1 -2x + 5

x^2 - 2x + 6

6 0

3 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

Todd hired a handyman to replace some tiles in his bathroom. He paid him $24 per hour of work and $15 as a tip.

Citrus2011 [14]

He paid him : 24t + 15

for 3 hrs...
24(3) + 15 = 72 + 15 = $ 87

4 0

3 years ago