The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
9/5
the distance is 9 over, and 5 up.
3 and 60 are the extremes while 15 and 12 are the means.
Answer:
use desmos. It really helps!
Step-by-step explanation:
<h2>
Answer:</h2>
Step-by-step explanation:
yeah
